The magnitude of a moment about a line segment connecting points Pand Q due to a force F applied at point R (with R not on the line through P and Q) can be calculated using the scalar triple product, Part A - Finding the scalar triple product Which of the following equations correctly evaluates the scalar triple product of three Cartesian vectors R, S, and T? MPQ = uPQ · r × F, • View Available Hint(s) where r is a position vector from any point on the line through P and Q to R and upo is the unit vector in the direction of line segment PQ. The unit vector uPQ is then multiplied by this magnitude to find the vector representation of the moment. O R.SxT= R,(S,T; – S;T,)+ R,(S„T; – S;T;) +R:(S„Ty – S,Tz) O R.S× T = R,(S,T; – S;T,) i+ R„(S,T; – S;T.) j+ R:(S,T, – S„T,) k O R.Sx T= R,(S,T; – S-T,) i – R,(S„T; – S;T2) j+R:(S,T, – S„T2) k O R.Sx T = R,(S„T; – S,T,) – R„(S„T; – S;T.) + R:(S„T, – S„T„) As shown in the figure, the member is anchored at A and section AB lies in the x-y plane. The dimensions are x1 = 1.6 m, Y1 = 1.7 m, and z1 = 1.6 m. The force applied at point C is F = [-185 i+ 80 j+ 190 k] N. Submit (Figure 1) Part B - Calculating the moment about AB using the position vector AC Using the position vector from A to C, calculate the moment about segment AB due to force F. Figure < 1 of 1> Express the individual components to three significant figures, if necessary, separated by commas. • View Available Hint(s) vec ? MAB =[ i, j, k] N · m B Submit

The magnitude of a moment about a line segment connecting points Pand Q due to a force F applied at point R (with R not on the line through P and Q) can be calculated using the scalar triple product, Part A - Finding the scalar triple product Which of the following equations correctly evaluates the scalar triple product of three Cartesian vectors R, S, and T? MPQ = uPQ · r × F, • View Available Hint(s) where r is a position vector from any point on the line through P and Q to R and upo is the unit vector in the direction of line segment PQ. The unit vector uPQ is then multiplied by this magnitude to find the vector representation of the moment. O R.SxT= R,(S,T; – S;T,)+ R,(S„T; – S;T;) +R:(S„Ty – S,Tz) O R.S× T = R,(S,T; – S;T,) i+ R„(S,T; – S;T.) j+ R:(S,T, – S„T,) k O R.Sx T= R,(S,T; – S-T,) i – R,(S„T; – S;T2) j+R:(S,T, – S„T2) k O R.Sx T = R,(S„T; – S,T,) – R„(S„T; – S;T.) + R:(S„T, – S„T„) As shown in the figure, the member is anchored at A and section AB lies in the x-y plane. The dimensions are x1 = 1.6 m, Y1 = 1.7 m, and z1 = 1.6 m. The force applied at point C is F = [-185 i+ 80 j+ 190 k] N. Submit (Figure 1) Part B - Calculating the moment about AB using the position vector AC Using the position vector from A to C, calculate the moment about segment AB due to force F. Figure < 1 of 1> Express the individual components to three significant figures, if necessary, separated by commas. • View Available Hint(s) vec ? MAB =[ i, j, k] N · m B Submit