The matrix A=0 0 -87-4 4 -8028has a single real eigenvalue A = 4 with algebraic multiplicity three.(a) Find a basis for the associated eigenspace.Basis = {(b) Is the matrix A defective?DA. A is defective because it has only one eigenvalueOB. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicityOc. A is not defective because the eigenvalue has algebraic multiplicity threeOD. A is not defective because the eigenvectors are linearly independent

Introduction: The matrices that have an eigenvalue decomposition are those that are not faulty.…

The matrix A = 0 -87 -8 2 0 8 has a single real eigenvalue X (a) Find a basis for the associated eigenspace. Го Basis = { }. -4 4 = 4 with algebraic multiplicity three. (b) Is the matrix A defective? DA. A is defective because it has only one eigenvalue foctive because the geometric multiplicity of the eigenvalue is less than the algebraic multiplici

The matrix A = 0 -87 -8 2 0 8 has a single real eigenvalue X (a) Find a basis for the associated eigenspace. Го Basis = { }. -4 4 = 4 with algebraic multiplicity three. (b) Is the matrix A defective? DA. A is defective because it has only one eigenvalue foctive because the geometric multiplicity of the eigenvalue is less than the algebraic multiplici

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter4: Eigenvalues And Eigenvectors

Section4.1: Introduction To Eigenvalues And Eigenvectors

Problem 26EQ

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