The motorcycle is traveling at a constant speed of 66km/h (Figure 1) Part A Determine the magnitude of its acceleration when it is at point A Express your answer to three significant figures and include the appropriate units. µA ? a = Value Units Submit Reguest Answer Figure < 1 of 1 < Return to Assignment Provide Feedback 2r 25 m
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- Specifically a dynamics problem: Two rockets start from rest at the same elevation. Rocket A accelerates vertically at 20 m/s2 for 12 s and then maintains a constant speed. Rocket B accelerates at 15 m/s2 until reaching a constant speed of 150 m/s.Construct the a-t, v-t, and s-t graphs for each rocket until t = 20 s. What is the distance between both rockets when t = 20 s?if the relation is : x=-153 + 10t + 4 1- the displacement between t1=2 ,t2=3 2- the magnitude of average velocity between t1=2,t4=4 3- the magnitude of average acceleration between t1=1,t4=5 4- the instantaneous velocity at t=2 5- the instantaneous acceleration at t=2The displacement of aparticle which moves along the s axis is given by s=(-2+3t)e-0.5t,where s is in meters and t is in seconds.Plot the displacement,velocity and acceleration versus time for the first 20 seconds of motion. Detrmine the time at which acceleration is zero.
- Find out the a.) Acceleration, b.) Speed at the 3.0s mark, and c.) Displacement at the 3.0s mark. Given the following initial conditions initial velocity=0 mass=5kg, static friction coefficient=0.4 kinetic friction coefficient=0.2, and angle of inclination =30degreePlease solve for: -Magnitude of acceleration of the rocket in m/s^2-Direction of acceleration of the rocket relative to the ground in degrees Box these answers, the unknowns that are asked for in the problem statement aren't necessary. v = 6 m/s^2p = 3000 kmThe 100 meter diameter wheel needs to be designed so that it rotates at a constant rate and every complete revolution takes 15 minutes. The wheel has been installed in a vertical plane and the lowest seat is 2m above the ground surface. Each ride consists of only one full rotation. Find a further general expression for the horizontal displacement of the rider from its initial position with respect to both time and angle of rotation and hence determine the speed of the rider when t= 180 sec. Using calculus, determine what the maximum horizontal and vertical speeds of the rider would be and at which points during the ride they occur. State expressions for the acceleration of the rider in both horizontal and vertical directions and show that the resultant acceleration experienced by the rider is independent of where on the ride he/she might be. In designing a new wheel with the same diameter and same ride duration as before it is proposed that the wheel’s angular speed should not…
- Applying principles of dynamics, with step by step solutions pls (i give 5 stars) A freighter is moving at a speed of 8 nautical miles per hour. The engines then had to be suddenly stopped. If it takes 10 minutes for the freighter to reduce its speed to 3 knots, determine the distance moved by the ship and its speed at the end of this interval. The deceleration of the ship is propor-tional to the square of its speed such that a = -kV^2.The velocity of a particle changes from -8 fps to 58 fps during a 10-sec intervalduring which its acceleration increases uniformly with the time from an initial valueof 3 fps2. Determine the displacement covered in the 10-sec interval. Draw the v-tand s-t curves.Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. Block B starts from rest and then moves to the right with a variable acceleration given by the acceleration-time curve. Determine:(a) the acceleration(b) the velocity of block A at t = 3.71 s.*dont copy other experts' answer, i'm looking for a different approach in solution can you please verify which among these two solutions is coreect?Solution 1: Step 1 Let T is the tension in each rope so 3T is acting on block B and 2T is acting on block A. So , 3T×aB=2T×aA×aB=2T×aA Hence,aA =32aBHence,aA =32aB Step 2 acceleration of block B = 0.29 ft/s2 (from graph) a)acceleration of block A (t=3.71s)= 32×0.29 ft/s2 =0.435 ft/s232×0.29 ft/s2 =0.435 ft/s2 b) Velocity of block B at (t = 3.71 s) = Area under the graph = 2ft/s2×1s−1ft/s2×1s+12×(2ft/s2+0.29ft/s2)×1.71s =2.96ft2ft/s2×1s-1ft/s2×1s+12×(2ft/s2+0.29ft/s2)×1.71s =2.96ft/s Velocity of block A at (t=3.71s) = 32×vB=32×2.96ft/s=4.44 ft/s Solution 2: *check the last…
- You are driving South on I-29. You realize that you are late for an appointment and speed up. With angular velocity and angular acceleration, respectively, which of the following statements is necessarily correct about the period of acceleration? A). For all wheels of your car, velocity points East and acceleration points West. B). For the right front wheel, both velocity and acceleration point East. C). For the left rear wheel, both velocity and acceleration point South D). For the left rear wheel, both velocity and acceleration point West.In a physics lab experiment, you release a small steelball at various heights above the ground and measure the ball’s speedjust before it strikes the ground. You plot your data on a graph that hasthe release height (in meters) on the vertical axis and the square of thefinal speed (in m2/s2) on the horizontal axis. In this graph your datapoints lie close to a straight line. (a) Using g = 9.80 m/s2 and ignoringthe effect of air resistance, what is the numerical value of the slope ofthis straight line? (Include the correct units.) The presence of air resistancereduces the magnitude of the downward acceleration, and the effectof air resistance increases as the speed of the object increases. Yourepeat the experiment, but this time with a tennis ball as the object beingdropped. Air resistance now has a noticeable effect on the data. (b) Isthe final speed for a given release height higher than, lower than, or thesame as when you ignored air resistance? (c) Is the graph of the releaseheight…Q#05 (b) : Explain the construction of Velocity and Acceleration diagrams.