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- :Binary-Decimal / Decimal Binary . Between 0 and 255 a number will be decided randomly by computer. Then asks to user 3 times a random digit of binary value of the that number. If user enters wrong number for a digit program will select another random number and ask random times random digit. For example: Computer selected number as 163 ( Which is 10100011) What is the digit 2 (question 1/3) :User enter 1 CorrectWhat is the digit 4 (question 2/3) : User enter 0 CorrectWhat is the digit 7 (question 3/3) : User enter 0 CorrectUser finished the quest with 3 input .61. State true or false: If I = read(Q) and J = read(Q) then the order of I and J does not matter. a. True b. False c. May be d. Can't say62. State true or false: If I = read(Q) and J = write(Q) then the order of I and J does not matter. a. True b. False c. May be d. Can't say
- 3. Take three numbers from the user and print the greatest number. Test DataInput the 1st number: 25 Input the 2nd number: 78 Input the 3rd number: 87Expected Output :The greatest: 87PSEUDO CODE MAKE CODE COMPLETE. 1024: OUTPUT getNumber: Read Base Read Exponent NumExponent(Base, Exponent); NumExponent(Base, Exponent): If Exponent=0 Return 1 Else Return Base*NumExponent(Base, Exponent-1).Extend to also output in reverse. Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy Howdy z 3.77 99
- 5. Write the python code which selects a random number between 1 and 10, once. Prompt the user for input until they guess the random number. Print congratulation once they guess it. 6. Write a program from decimal to any base, ask the user for a decimal number and convert entered base by user. (Your program should support bases between 2 and 16 .)Complete and modify the code: 1 def neg(x): 2 """Return the negated input number 3 4 >>> neg(5) 5 -5 6 7 """ 8 9 return x 10 11 neg(-10) 12 neg(0) 13 neg(91)The following program has syntax errors. Correct them. On each successive line, assume that any preceding error has been corrected. (12) const char = STAR = '*' const int PRIME = 71; int main { int count, sum; double x; count = 1; sum = count + PRIME; x = 25.67 newNum = count * ONE + 2; sum + count = sum; (x + sum) ++; x = x + sum * COUNT; sum += 3 ; cout " count = " count ", sum = " sum ", PRIME = " Prime endl; }
- Using DevC++ Write a program that allows the user to type in up to 10 positive numbers and then echoes back the numbers typed in but in reverse order. Binary-Decimal / Decimal Binary . Between 0 and 255 a number will be decided randomly by computer. Then asks to user 3 times a random digit of binary value of the that number. If user enters wrong number for a digit program will select another random number and ask random times random digit. Every time user enters input will be counted as one hour in that planet. For example: Computer selected number as 163 ( Which is 10100011) What is the digit 2 (question 1/3) :User enter 1 CorrectWhat is the digit 4 (question 2/3) : User enter 0 CorrectWhat is the digit 7 (question 3/3) : User enter 0 CorrectUser finished the quest with 3 input .#include <iostream>#include <cmath>#include <iomanip>using namespace std; int main() { double x; double y; double z; cin >> x; cin >> y; /* Your code goes here */ cout << fixed << setprecision(1); // setprecision(1) outputs z with 1 decimal place. cout << z << endl; return 0;} having trouble with this code in C++