The network shown in the figure below is assembled with uncharged capacitors X, Y, and Z, with Cx 7 uF, Cy=8 μF, and Cz = 5 μF and open switches, S₁ and S2. A potential difference Vab +120 V is applied between points a and b. After the network is assembled, switch S₁ is closed for a long time, but switch S2 is kept open. Then switch S₁ is opened and switch S₂ is closed. What is the final voltage across capacitor X? V₁ = +120 V b (A) 100 V (B) 92 V (C) 76 V (D) 67 V (E) 84 V X Z
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- Short Problem: Given a parallel RLC circuit comprised of the following element: 62.52-ohm resistor, ideal inductor with reactance of 33.15 ohms; and a capacitor with reactance of 6.11 ohms. Compute for true power in watts given an ac voltage source of 100 cis 0 volts. PLEASE ANSWER WITHIN 30 MINUTES. Round off to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation. Use stored values. Write the numerical values only. No units in your final answer. Spaces are not allowed.a series r-c circuit takes a current whose equation is i=0.85sin(754t+pi/4) when connected to a source of emf having the equation e=340sin754t. calculate the capacitance of the capacitor, circuit power factor, and power.Show the complete solution. 25. How many time constants one should wait for the current in an RL circuit to grow within 0.1% of its steady state value? Answer: 6.9 26. A coll of inductance 5 H and resistance 100 ohms carries a steady current of 2 A. Calculate the initial rate of fall of current in the coll after a short circuiting switch is connected across its terminals has been suddenly closed. Answer: -40 A/s
- In the circuit of the figure, the switch S has been in position a for a long time; when the current through the inductor is maximum, the switch changes to position b (this instant is taken as t = 0). If the current source is iS(t) = 2.1213 cos (100πt + π/ 4). Determine: i) the value of R2 so that at t = 4 mS the current iL (t = 4mS) = 1 A. ii) The expression for the inductor current iL(t) t> 0 iii) the value of iL(t) at t = 0. iv) the expression of the inductor voltage vL(t) t> 0. v) the value of vL(0).In the circuit given below, R = 14 Ω. The switch in the circuit moves from position A to position B at t = 0 (please note that the switch must connect to point B before it breaks the connection at A, a make-before-break switch). Determine i(t) for t > 0. a) i(t) = e–3.571t (0.726 sin(19.679t)) A b) i(t) = e–3.571t (4 cos(19.679t)) A c) i(t) = e–3.571t (4 cos(19.679t) – 0.726 sin(19.679t)) A d) i(t) = e–3.571t (4 cos(19.679t) + 0.726 sin(19.679t)) AThe circuit shown in the attached image contains a voltage source with emf ε = 2.99 V, a resistor with resistance R = 135 kΩ, and a capacitor with capacitance C = 612 nF. When switch S is set to position a, the three circuit elements are in series. When the switch is in position b, the battery is excluded from the circuit. The switch is initially moved to position a, where it remains for a sufficiently long time that the capacitor is fully charged. The switch is now moved to position b. What is the magnitude of the instantaneous current, in amperes, through the resistor the instant the switch makes contact with terminal b? With time meausred the instant that switch S is closed in position b, calculate the time, in seconds, when the charge on the capacitor is one-half of its maximum value. Calculate the current through the resistor, in amperes, at time t = 155.5 ms after the switch is closed in position b.
- Show your complete solution and attached it here. Answer must be in 4 decimal places. An industrial coil is modeled as a series combination of an inductance L and resistance R. Since an ac voltmeter measures only the magnitude of a sinusoid, the following measurements are taken at 60 Hz when the circuit operates in the steady-state: |Vs| = 145 V, |V1| = 50 V, |Vo| = 110 V Use these measurements to determine the values of L and R.You are investigating the electrical testing circuits and find that, in an inductive circuit, the relationship between instantaneous current i (amps) and the time t (secs) is given by: i = 12.5(1-e-t/CR) You have been asked to determine the time taken for the current to rise from 1 to 2 amps given your own R and C values as follows. R= 140 C= 90Short Problem: Given a parallel RLC circuit comprised of the following element: 97.19-ohm resistor, ideal inductor with reactance of 36.14 ohms; and a capacitor with reactance of 16.25 ohms. Compute for true power in watts given an ac voltage source of 100 cis 0 volts. Note: Follow this reminder carefully. Compute to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation. Use stored values. Write the numerical values only. No units in your final answer. Spaces are not allowed. Excessive number of decimals as compared to the required number of decimals may result to an incorrect answer.
- RC Circuit Charging Capacitor R= 1 MW, C= 470 mF, Vs= 10 v Time t(s) Vc(v) 0 0 60 1.2 120 2.3 180 3.2 240 4 300 4.7 360 5.4 400 5.7 460 6.2 520 6.7 580 7 700 7.8 820 8 940 8.6 1060 9 1180 9.2 1300 9.4 1420 9.5 Texp= Tth= Conclusion: ................................................................................................................................................................................given the circuit below , find and plot the current ix(t) for t>0s A=3A resistors=2 ohms each anc capacitor=1/4F voltage source is 3ix. solve in great detail.Calculate the equivalent capacitance in the circuit. Enter your answer in µF rounded to 2 decimal places. All capacitors were initially discharged. at t = 0, S1 is placed at position 1 and S2 is closed. At t = 15 ms, S1 is placed at position 2 and S2 is kept closed. At t = 25 ms, S1 is kept at position 2 and S2 is opened. Data: V1 = 19 V; R1 = 7.5 kΩ, R2 = 5 kΩ, R3 = 2.0 kΩ, R4 = 2 kΩ, R5 = 20 kΩ, R6 = 9.0 kΩ; C1 = 4.5 µF, C2 = 6.0 µF, C3 = 13 µF