The number of pets per household in in a certain neighborhood varies from 0 to 6. The probability distribution of the number of pets owned by a random household, X,

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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The number of pets per household in in a certain neighborhood varies from 0 to 6. The probability distribution of the number of pets owned by a random household, X, is as follows:
The number of pets per household in a certain neigborhood varies from 0 to 6. The probability distribution
of the number of pets owned by a random household, X, is as follows:
1
2
3
4
6.
Total
P(X = ri)
0.02
0.1
0.19
0.41
0.16
0.1
0.02
1
1. Use the random variable notation to express symbolically each of the following:
The probability that the number of pets owned by a random household is
exactly 2.
The probability that the number of pets owned by a random household is
exactly 4 is equal to 0.16.
An event in which the number of
owned by a random household is
exactly 1.
2. Use the above probability distribution table to find the following:
a. Р(2 < X < 3) —
(Round the answer to 2 decimals)
b. H(5 < X < 6) =
(Round the answer to 2 decimals)
с. Р(X > 0) —
(Round the answer to 2 decimals)
Transcribed Image Text:The number of pets per household in a certain neigborhood varies from 0 to 6. The probability distribution of the number of pets owned by a random household, X, is as follows: 1 2 3 4 6. Total P(X = ri) 0.02 0.1 0.19 0.41 0.16 0.1 0.02 1 1. Use the random variable notation to express symbolically each of the following: The probability that the number of pets owned by a random household is exactly 2. The probability that the number of pets owned by a random household is exactly 4 is equal to 0.16. An event in which the number of owned by a random household is exactly 1. 2. Use the above probability distribution table to find the following: a. Р(2 < X < 3) — (Round the answer to 2 decimals) b. H(5 < X < 6) = (Round the answer to 2 decimals) с. Р(X > 0) — (Round the answer to 2 decimals)
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