The orthogonal trajectory of y= Ce" is a parabola of the form y = ax+b. what is the value of b so that the vertex is at (88,0)?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.6: Quadratic Functions
Problem 1E
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The orthogonal trajectory of y= Ce*
is a parabola
of the form Y =ax+b. what is the value of b so
that the vertex is at (88,0)?
Transcribed Image Text:The orthogonal trajectory of y= Ce* is a parabola of the form Y =ax+b. what is the value of b so that the vertex is at (88,0)?
Which of the following is a member of the family of
orthogonal trajectory of y Csin(x)
(A All of the above
y-e-2n(sec ()
© - In(5) - 2sec?x)-tan (x)
O-In(5) - sec (x)-tan?(x)
O y? = e+ 2ln(cos(x))
Transcribed Image Text:Which of the following is a member of the family of orthogonal trajectory of y Csin(x) (A All of the above y-e-2n(sec () © - In(5) - 2sec?x)-tan (x) O-In(5) - sec (x)-tan?(x) O y? = e+ 2ln(cos(x))
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