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Genetics Question 5
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- QUESTION NO. 1 A transition mutation A. occurs when a purine is substituted for a pyrimidine or vice versa. B. results from the insertion of one or two bases into the DNA chain. C. is most frequently caused by chemicals (like acridine) that intercalate into DNA. D. results from substitution of one purine for another or of one pyrimidine for another. E. always is a missense mutation QUESTION NO. 2 Degeneracy of the generic code denotes the existence of A. multiple codons for a single amino acid. B. codons consisting of only two bases. C. base triplets that do not code for any amino acid. D. different systems in which a given trip let codes for different amino acids. E. codons that include one or more of the unusual bases. QUESTION NO. 3 Replication A. requires that a phosphodiester bond of the incoming dNTP be hydrolyzed in order to be added to the growing chain. B. uses 5' to 3' polymerase activity to synthesize one…QUESTION 27 Which of the following methods can be used to compare the amounts of one specific mRNA that is expressed by two different cell lines? A. Immunohistochemistry B. Western blotting C. Polymerase chain reaction (PCR) D. ImmunocytochemistryQuestion- 1. In onions, male sterility is due to the interaction of a chromosomal allele pair hh and “sterile” (S) cytoplasm. All other combinations (i.e. HH/Hh and “sterile” cytoplasm, HH/Hh or hh “fertile” (F) cytoplasm) result in male-fertile plants. The male-sterile trait is incorporated into inbred lines to produce hybrid F1 seed on a commercial scale.a) How would you perpetuate the male-sterile line? Show the cross.b) Briefly outline the method of producing hybrid seed (heterozygote) for the commercial crop. Show the cross.c) Does it matter whether the cytoplasm is fertile or sterile in the male-fertile inbred? Explain.
- QUESTION 24 During lagging strand synthesis of DNA, Okazaki fragments are linked together by ___________. DNA polymerase I Primase Beta clamps DNA LigaseQUESTION 1 Select the letter of the most appropriate answer. - A. B. C. D. E. F. G. H. I. J. K. L. M. N. examples include base substitutions and deletions - A. B. C. D. E. F. G. H. I. J. K. L. M. N. person who has one recessive allele for a recessive genetic disorder - A. B. C. D. E. F. G. H. I. J. K. L. M. N. type of DNA used to prepare a DNA profile - A. B. C. D. E. F. G. H. I. J.…Question 44 Along with modification of histones and positioning of nucleosomes, following is one of the main epigenetic mechanisms operating across the genome: Question 44 options: DNA acetylation DNA methylation DNA oxidation DNA phosphorylation Question 45 Changes in our DNA that have not been corrected by cellular DNA repair systems create: Question 45 options: Transcripts DNA variants Polypeptide Polynucleotide Question 46 The degeneracy of the genetic code most often involves: Question 46 options: the third base of the codon the second base of the codon the first base of the codon two bases of the codon
- QUESTION NO. 1 Patients with the rare genetic disease xeroderma pigmentosum (XP) are very sensitive to light and are highly susceptible to skin cancers. The study of such patients has enhanced our knowledge of DNA repair because XP is caused by defective DNA repair nucleotide excision repair. (A variant, XP-V, is deficient in postreplication repair.) In nucleotide excision repair A. removal of the damaged bases occurs on only one strand of the DNA. B. only thymine dimers generated by UV light can be removed . C. the excision nuclease is an exonuclease. D. a single multifunctional enzyme carries out the repair process. E. only the damaged nucleotides are removed. QUESTION NO.2 Homologous recombination: A. occurs only between two segments from the same DNA molecule. B. requires that a specific DNA sequence be present. C. requires one of the duplexes undergoing recombination be nicked in both strands. D. involves a…Question:- 1. A brand-new deleterious allele has just entered a population via mutation; this allele had not existed before in the population. If its allele frequency in the next generation is 0.00000021, what must have the mutation rate have been of these gene? 2. Use #1 to answer. Using standard scientific notation format, enter the exponent (including the negative sign).Question Number-1: Using complementary base pairing method, convert the following DNA sequence into RNA sequence. DNA: TACGGCGCGTATACGACT
- QUESTION 25 During lagging strand synthesis of DNA, the RNA primers are replaced with DNA by __________. DNA Polymerase I DNA Polymerase II DNA Polymerase III PrimaseQuestion:- 1. Brassica oleracea is the wild plant from which brussels sprouts, cabbage, broccoli, and cauliflower were domesticated. Why is it important to keep many diverse seeds from the forb B. oleracea across its range? A. If our B. oleracea-derived crops are driven to extinction, we can re-domesticate them from the wild plant. B. Our crop Brassicas are much more genetically diverse than B. oleracea because of extensive breeding programs, so we need to conserve as much of B. oleracea's diversity as possible. C. The budding pattern in Brassica may be further modified to produce more productive crop plants. D. B. oleracea may have gene variants that can be incorporated into our domesticated plants to increase their environmental range or tolerance to pests. E. We may be able to domesticate another crop plant from B. oleracea.Question: 1. The binomial expression for two alleles in haploid organisms is (p + q) = 1.0. If a new mutation occurs at a given locus in a bacterium at a frequency of 1 x 10-6. What is the frequency of the wild type allele at that locus?