The perimeter of a rectangular garden is 48 feet. The length of the garden is 2 feet more than the width. Determine the dimensions of the garden by solving the following system of equations, where L and W represent the length and width of the garden. 2L+2W L = 48 = W+2 *** The width of the garden is feet. (Type an integer or a decimal.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter6: Systems Of Linear Equations And Inequalities
Section6.2: Substitution
Problem 37PFA
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The perimeter of a rectangular garden is 48 feet. The length of the garden is 2 feet more than the width. Determine the
dimensions of the garden by solving the following system of equations, where L and W represent the length and width
of the garden.
2L+2W = 48
L
= W + 2
LUT
The width of the garden is feet. (Type an integer or a decimal.)
View an example Textbook
Your Answer Is Keaay
Transcribed Image Text:The perimeter of a rectangular garden is 48 feet. The length of the garden is 2 feet more than the width. Determine the dimensions of the garden by solving the following system of equations, where L and W represent the length and width of the garden. 2L+2W = 48 L = W + 2 LUT The width of the garden is feet. (Type an integer or a decimal.) View an example Textbook Your Answer Is Keaay
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