The pipe assembly supports the vertical loads shown. Determinethe components of reaction at the ball-and-socket joint A and thetension in the supporting cables BC and BD.Equations of Equilibrium:Converting all forces in vector form;Given:TBp = TBDUBD = TBD2mF = 6 kNTBD =|T80 i+TBD j+F2 = 4 kN2mTBCTBc = TBCUBC = TgcIacl,1.5m1.5mTBC =Tsc i+Tscj+Tsck1m2mThe reaction forces at point A can be eliminated by writing themoment equation of equilibrium about point A.3m6 kN4 kNim 1.5m.y3mΣΜΑ-0TAB X (TBp + Tạc) + (r, x F,) + (r; x F;)= 0Free body diagram (FBD):-r, is the distance from point A to F,. Since r, is directed along y axis,therefore, r, = 0i + 4j + Okr, is the distance from point A to F2. Since r, is directed along y axis,therefore, r, = 0i + 5.5j + Ok r, is the distance from point A to F,. Since r, is directed along y axis,therefore, r, = 0i +5.5j + Okl'AB =i +IkTABX"ABY"ABzriyrzyΣΜΑ-|(TBD + TBc)x (TEp + Tgc)y (Typ + Tgc)=|*|F1x Fay F12Fayo-Apply the equation of equilibrium, EM,=0, EM,-0 and EM,=0and solve the equation simultaniouslyTBDkNIkNRepresenting force at point A as F,=A, i +A, j+A,kThen, applying the force equation of equilibrium, EF,=0, EF,=0 andEF,=0 and solve the equation simultaniouslyA,kNAy =kNkN

Fro the given Free body diagram(FBD) F1 =6 kN and F2=4 kN Now by considering A as origin the…

The pipe assembly supports the vertical loads shown. Determine Equations of Equilibrium: the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Converting all forces in vector form; Given: Tạp = TapUBD = TBD F.= 6 kN 2m Tạp = Ta0 i+ F2= 4 kN 2m BC Tạc = TạcUBc = 1.5m Tạc =| 1m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 2m 4 kN 1m 1.5m. 3m IMA = 0

The pipe assembly supports the vertical loads shown. Determine Equations of Equilibrium: the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Converting all forces in vector form; Given: Tạp = TapUBD = TBD F.= 6 kN 2m Tạp = Ta0 i+ F2= 4 kN 2m BC Tạc = TạcUBc = 1.5m Tạc =| 1m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 2m 4 kN 1m 1.5m. 3m IMA = 0

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter4: Coplanar Equilibrium Analysis

Section: Chapter Questions

Problem 4.72P: Draw the FBDs for the entire structure and the member BDE. Count the total number of unknowns and...

See similar textbooks

Similar questions

Draw the FBDs for the beam ABC and the segments AB and BC. Note that the two segments are joined by a pin at B. Count the total number of unknowns and the total number of independent equilibrium equations.
Given the wall crane supports an additional 700 lb. load, the force on the cable at the winch motor W and the horizontal and vertical component of the pin reactions at A, B, C, and D. Apply the equations of equilibrium and solve the unknowns.
Each cord can sustain a maximum tension of 200N. Determine the largest weight of sack that can be supported. Also determine angle of cord DC for equilibrium.
The jib crane is pin connected at A and supported by a pin connected collar on smooth rod at B. If x = 6.0 ft , determine the reactions on the jib crane at the pin A and smooth collar B. The load has a weight of 5500 lb Determine the reactions on the jib crane at the pin A Determine the reaction at B
The mass of crate D is held in position by two blocks, B and C, which are attached to the ring at A. The angle that rope AC makes in a counterclockwise direction from the positive x-axis is theta=30 rad as shown. The mass of block B is equal to that of C, mB=mC=158 kg a) draw the free body diagram of the point of equilibrium b) write down the static equilibrium equations c) determine the angle phi and tge weight of block D f) why will point A be the midpoint between B and C? Explain e) if all three weights are equal can equilibrium be maintained?
A box of 25 kg is attached to the frame shown below. The frame is in equilibrium and slotted member DE is vertical. Determine the tension in the spring and the reactions at F (g=9.81 m/s2). (draw free body diagram)
Q (4): The 11 Kg lamp fixture is suspended from the two springs, each having an unstretched length of 6 m. Determine stiffness of k for equilibrium.
Determine the reactions at A and E if P = 310 N. What is the maximum value which P may have for static equilibrium? Neglect the weight of the structure compared with the applied loads.
Activity 2: Determine the weight W and the horizontal and vertical components of the pin reaction at A for equilibrium assuming all bearings are frictionless. Beam AB weighs 600 KN.
Equilibrium problem r1+ r2 and w=wxd
Determine the weight W and the horizontal and vertical components Of the pin reaction at A for equilibrium assuming all bearings are frictionless. Beam AB weighs 600 KN.
A 120-lb weight is attached to the cable that is wrapped around the 50-lb homogeneous drum. Theshaft attached to the drum is supported by a thrust bearing at A and a slider bearing at B. The drum iskept in equilibrium by the vertical force P acting on the handle of the crank. Determine P and thereactions at A and B. Neglect the weights of the crank and the shaft. Provide a free-body-diagram.