The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of other factors, the population doubles each week. There are 900,000 mosquitoes in the area initially, and predators (birds, bats, and so forth) eat 70,000 mosquitoes/day. Determine the population of mosquitoes in the area at any time t, measured in days. NOTE: Enter an exact answer. P(t) %3D

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.3: Least Squares Approximation
Problem 33EQ
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Please solve & show steps... the answer is NOT P(t) = 706920.57+193079.43e^(0.01t)... 

The population of mosquitoes in a certain area increases at a rate
proportional to the current population, and in the absence of
other factors, the population doubles each week. There are
900,000 mosquitoes in the area initially, and predators (birds,
bats, and so forth) eat 70,000 mosquitoes/day. Determine the
population of mosquitoes in the area at any time t, measured
in days.
NOTE: Enter an exact answer.
P(t)
Transcribed Image Text:The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of other factors, the population doubles each week. There are 900,000 mosquitoes in the area initially, and predators (birds, bats, and so forth) eat 70,000 mosquitoes/day. Determine the population of mosquitoes in the area at any time t, measured in days. NOTE: Enter an exact answer. P(t)
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