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The pre-image in red has been transformed to the image in green. Select the equations for both images. O f (x) = -(x + 1)ª – 1 O f (æ) = -(* – 1)ª + 1 O f (æ) = - (x + 1)* + 1 O f (x) = (x + 1)ª + 1 %3D O f (2) = -(* –- 1)* – 1 O f (x) = (x – 1)ª +1 O f (12) = (x + 1)ª – 1

The pre-image in red has been transformed to the image in green. Select the equations for both images. O f (x) = -(x + 1)ª – 1 O f (æ) = -(* – 1)ª + 1 O f (æ) = - (x + 1)* + 1 O f (x) = (x + 1)ª + 1 %3D O f (2) = -(* –- 1)* – 1 O f (x) = (x – 1)ª +1 O f (12) = (x + 1)ª – 1

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter7: Exponents And Exponential Functions
Section7.7: Writing Exponential Functions
Problem 39PFA
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Answer this question for me mate. Much appreciated. :)

The pre-image in red has been transformed to the image in green. Select the equations for both images. 5 4 3 -2 -1 1 3 4 -1 -5 -6 O (æ) = - (x + 1)* – 1 O f (x) = -(x – 1)“ +1 O f (x) = -(x + 1)* + 1 O f (x) = (x + 1)“ + 1 O (x) = -(x – 1)* – 1 %3D O f (x) = (x – 1)“ +1 O f (2) = (x +1)* – 1
Transcribed Image Text:The pre-image in red has been transformed to the image in green. Select the equations for both images. 5 4 3 -2 -1 1 3 4 -1 -5 -6 O (æ) = - (x + 1)* – 1 O f (x) = -(x – 1)“ +1 O f (x) = -(x + 1)* + 1 O f (x) = (x + 1)“ + 1 O (x) = -(x – 1)* – 1 %3D O f (x) = (x – 1)“ +1 O f (2) = (x +1)* – 1
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