The procedure to solve a polynomial or rational inequality may be applied to all inequalities of the form f(x) > 0, f(x) < 0, f(x) > 0, and f(x) < 0. That is, find the real solutions to the related equation and determine restricted values of x. Then determine the sign of f(x) on each interval defined by the boundary points. Use this process to solve the inequalities in Exercises 109–120. 109. V2x – 6 – 2 < 0 110. V3x – 5 – 4 < 0 111. V4 – x – 6 > 0 1 1 112. V5 – x – 7>0 113. Vx - 2 - 4 114. Vx - 3 – 5 115. -3 < x - 6x + 5 < 5 117. x - 4| < 5 120. x – 6|> 3 116. 8 < x + 4x + 3 < 15 118. |x + 1|< 17 119. |x – 18|> 2

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.2: Transformations Of Quadratic Functions
Problem 50PFA
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The procedure to solve a polynomial or rational inequality may be applied to all inequalities of the form f(x) > 0, f(x) < 0,
f(x) > 0, and f(x) < 0. That is, find the real solutions to the related equation and determine restricted values of x. Then
determine the sign of f(x) on each interval defined by the boundary points. Use this process to solve the inequalities in
Exercises 109–120.
109. V2x – 6 – 2 < 0
110. V3x – 5 – 4 < 0
111. V4 – x – 6 > 0
1
1
112. V5 – x – 7>0
113.
Vx - 2 - 4
114.
Vx - 3 – 5
115. -3 < x - 6x + 5 < 5
117. x - 4| < 5
120. x – 6|> 3
116. 8 < x + 4x + 3 < 15
118. |x + 1|< 17
119. |x – 18|> 2
Transcribed Image Text:The procedure to solve a polynomial or rational inequality may be applied to all inequalities of the form f(x) > 0, f(x) < 0, f(x) > 0, and f(x) < 0. That is, find the real solutions to the related equation and determine restricted values of x. Then determine the sign of f(x) on each interval defined by the boundary points. Use this process to solve the inequalities in Exercises 109–120. 109. V2x – 6 – 2 < 0 110. V3x – 5 – 4 < 0 111. V4 – x – 6 > 0 1 1 112. V5 – x – 7>0 113. Vx - 2 - 4 114. Vx - 3 – 5 115. -3 < x - 6x + 5 < 5 117. x - 4| < 5 120. x – 6|> 3 116. 8 < x + 4x + 3 < 15 118. |x + 1|< 17 119. |x – 18|> 2
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