# The question says "factor the expression":(5a+1)2-2(5a+1)-3It says further down (this is an example from the text chapter), that the expression will factor as ((blank space)-3)((blank space)+1), and I think they're getting there with a trial/error method (-3+1=-2, -3*1=-3)? But I'm not sure where to take the problem from there, or why it only has 2 factors...

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The question says "factor the expression":

(5a+1)2-2(5a+1)-3

It says further down (this is an example from the text chapter), that the expression will factor as ((blank space)-3)((blank space)+1), and I think they're getting there with a trial/error method (-3+1=-2, -3*1=-3)? But I'm not sure where to take the problem from there, or why it only has 2 factors...

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To factor the ex...

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