Ex. 1840. Given two voltage functions with phases in degrees: V1=44sin(26t+74) V2=34cos(26t+41). Determine: V1_phasor=Aexp(jB) and V2_phasor=Cexp(jD) and V3_phasor=V1+V2=Eexp(jF). Express your angles in degrees between -90 and +90. Answers: A,B (deg),C,D (deg),E,F (deg). ans:6
Ex. 1840. Given two voltage functions with phases in degrees: V1=44sin(26t+74) V2=34cos(26t+41). Determine: V1_phasor=Aexp(jB) and V2_phasor=Cexp(jD) and V3_phasor=V1+V2=Eexp(jF). Express your angles in degrees between -90 and +90. Answers: A,B (deg),C,D (deg),E,F (deg). ans:6
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.3MCQ: If a phasor representation of a current is given by I=70.745A, it is equivalent to a. 100e/45 b....
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Ex. 1840. Given two voltage functions with phases in degrees: V1=44sin(26t+74) V2=34cos(26t+41). Determine: V1_phasor=Aexp(jB) and V2_phasor=Cexp(jD) and V3_phasor=V1+V2=Eexp(jF). Express your angles in degrees between -90 and +90. Answers: A,B (deg),C,D (deg),E,F (deg). ans:6
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The question states the angle must be within the range -90 to +90 how do I convert it to that
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