The rate of growth dP/dt of a population of bacteria is proportional to the square root of t, where P is the population size and t is the time in days (0 ≤ t ≤ 10) as shown below. dp/dt= k sq.rt. t The initial size of the population is 500. After 1 day the population has grown to 700. Estimate the population after 8 days. (Round your answer to the nearest whole number.) bacteria
The rate of growth dP/dt of a population of bacteria is proportional to the square root of t, where P is the population size and t is the time in days (0 ≤ t ≤ 10) as shown below. dp/dt= k sq.rt. t The initial size of the population is 500. After 1 day the population has grown to 700. Estimate the population after 8 days. (Round your answer to the nearest whole number.) bacteria
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 13EQ
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The rate of growth dP/dt of a population of bacteria is proportional to the square root of t, where P is the population size and t is the time in days (0 ≤ t ≤ 10) as shown below.
dp/dt= k sq.rt. t
The initial size of the population is 500. After 1 day the population has grown to 700. Estimate the population after 8 days. (Round your answer to the nearest whole number.)
bacteria
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