The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays. Watch TV Do Not Watch TV Workday 0.74 Not a Workday 0.13 0.11 0.02 For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities. The events are approximately independent because 0.871 ≈ 0.870. The events are not independent because 0.871 = 0.870. The events are approximately independent because 0.851 # 0.870. The events are not independent because 0.851 # 0.870.
The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays. Watch TV Do Not Watch TV Workday 0.74 Not a Workday 0.13 0.11 0.02 For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities. The events are approximately independent because 0.871 ≈ 0.870. The events are not independent because 0.871 = 0.870. The events are approximately independent because 0.851 # 0.870. The events are not independent because 0.851 # 0.870.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter12: Probability
Section12.CR: Chapter 12 Review
Problem 10CR
Question
![The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays.
Watch TV Do Not Watch TV
Workday
0.74
Not a Workday 0.13
0.11
0.02
For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities.
The events are approximately independent because 0.871 ≈ 0.870.
The events are not independent because 0.871 = 0.870.
The events are approximately independent because 0.851 # 0.870.
The events are not independent because 0.851 # 0.870.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4f22148c-14cb-4343-a792-3a404f2d908e%2F3711b75f-3512-4311-a770-ea430f740d00%2Fqwfnble_processed.png&w=3840&q=75)
Transcribed Image Text:The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays.
Watch TV Do Not Watch TV
Workday
0.74
Not a Workday 0.13
0.11
0.02
For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities.
The events are approximately independent because 0.871 ≈ 0.870.
The events are not independent because 0.871 = 0.870.
The events are approximately independent because 0.851 # 0.870.
The events are not independent because 0.851 # 0.870.
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