The Riemann sums for a function f on the interval [1, 5] are given as E (2 - u)Ax, where [1. 5] is partitioned into n subintervals [x-1. ] of width Ar; and u, is some number in [x,-1, ]. If lim E (2 – u)Ax, exists, it man A0 (2-4)Ax, exists, it equals (B) (2-)Ax (A) (O 2-dr (D) 2-rt

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 2SE: If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local...
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2. The Riemann sums for a function f on the interval [1, 5]
are given as (2 - u) Ax, where [1, 5] is partitioned
into n subintervals [x-1, X] of width Ax; and u, is some
number in [x,-1, X]. If lim E (2- u) Ax, exists, it
max Ax-0=
equals
(A)
(B) (2- u) Ax
(O(2-rds
(D) 2-ds
Transcribed Image Text:2. The Riemann sums for a function f on the interval [1, 5] are given as (2 - u) Ax, where [1, 5] is partitioned into n subintervals [x-1, X] of width Ax; and u, is some number in [x,-1, X]. If lim E (2- u) Ax, exists, it max Ax-0= equals (A) (B) (2- u) Ax (O(2-rds (D) 2-ds
Expert Solution
Step 1

Here the given function is continuous and non-negative defined on the closed interval [1, 5]

 

The given interval divided into n subintervals defined as:

 

1 = x0 < x1 < x2 < … < xi < … < xn = 5

 

The n subintervals is defined as:

 

[1, x1] , [x1, x2], … , [xn-1, 5]

 

the above subdivision is called partition of the given interval.

 

 

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