The series > Cnx" converges when x = -2 and diverges when x = 5. What can be said about the following series? n=0 00 (1) E Cn2" (II) en(-6)" n=0 n=0 (a) Both series diverge (b) Both series converge (c) I converges; II diverges (d) I cannot be determined; II diverges (e) Neither can be determined

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
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. The series > Cnx" converges when x = -2 and diverges when x = 5. What can be said about the following series?
n=0
(1) E
(II) Een(-6)"
Cn 2"
n=0
n=0
(a) Both series diverge
(b) Both series converge
(c) I converges; II diverges
(d) I cannot be determined; II diverges
(e) Neither can be determined
Transcribed Image Text:. The series > Cnx" converges when x = -2 and diverges when x = 5. What can be said about the following series? n=0 (1) E (II) Een(-6)" Cn 2" n=0 n=0 (a) Both series diverge (b) Both series converge (c) I converges; II diverges (d) I cannot be determined; II diverges (e) Neither can be determined
Expert Solution
Step 1

Here, we shall use the comparison test to conclude our solution.
 

The Limit Comparison Test for Series is given as

Let b(n) be a second series. Require that all a[n] and b[n] are positive.

  • If the limnanbn>0, then n=0an converges if and only if n=0bnconverges.
  • If the limnanbn=0, andn=0bn converges, thenn=0an also converges.
  • If thelimnanbn=, and n=0bn diverges, thenn=0an also diverges.
Step 2

II) We have to test the convergence of n=0cn(-6)n.

  Let n=0an = n=0cn(-6)n and n=0bn = n=0cn(-2)n, where we know thatn=0bn converges.

With an = cn(-6)n, bn=cn(-2)n, we evaluate limnanbn. Thus, 
limn anbn=limn cn(-6)ncn(-2)n             =limn (-6)n(-2)n             =limn n!.(-6)n!.(-2)     (L'Hospitals' Rule)             = 3 >0

 From Limit Comparison Test, we can see that n=0an = n=0cn(-6)n converges.

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