The shaft consisting of steel and aluminum segments carries the torques T and 2T. Find the largest allowable value of T if the working shear stresses are 12500 psi for steel and 7800 psi for aluminum and the angle of rotation at the free end must not exceed 6 degrees. Use G = 12×10^6 psi for steel and G = 4×10^6 psi for aluminum.

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Author:Segui, William T.
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Chapter5: Beams
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Problem 5.8.1P: Compute the nominal shear strength of an M107.5 of A572 Grad 65 steel.
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The shaft consisting of steel and aluminum segments carries the torques T and 2T. Find the largest allowable value of T if the working shear stresses are 12500 psi for steel and 7800 psi for aluminum and the angle of rotation at the free end must not exceed 6 degrees. Use G = 12×10^6 psi for steel and G = 4×10^6 psi for aluminum.
consisting of steel and aluminum segments carries the torques
owable value of T if the working shear stresses are 12500 psi for s
and the angle of rotation at the free end must not exceed 6 degre
12 x 106 psi for steel and G = 4 x 106 psi for aluminum.
T
Aluminum
2 ft
1.6 in dia.
2T
Steel
3.2 ft
2 in dia.
Checked by:
Noted by:
ANG, RCE
JOHN TROY S. BORROMEO, RCE
FRANCISCO B. CUI
Program Head, BSCE
Dean, College of E
Transcribed Image Text:consisting of steel and aluminum segments carries the torques owable value of T if the working shear stresses are 12500 psi for s and the angle of rotation at the free end must not exceed 6 degre 12 x 106 psi for steel and G = 4 x 106 psi for aluminum. T Aluminum 2 ft 1.6 in dia. 2T Steel 3.2 ft 2 in dia. Checked by: Noted by: ANG, RCE JOHN TROY S. BORROMEO, RCE FRANCISCO B. CUI Program Head, BSCE Dean, College of E
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