The smaller the curvature in the bend of a road, the faster a car can travel. Assume that the maximum speed around a turn is 3 inversely proportional to the square root of the curvature. A car moving on the path y = x3 (x and y are measured in miles) (1, -1/-). How fast can it go at (6/5, 72/125)? (Round your answer to two decimal places.) can safely go 30 miles per hour at mi/hr Nood Help? Road it

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A: We can solve this as follows:

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