The solution of a certain differential equation is of the form y(t) = aest + bet, where a and b are 5t constants. The solution has initial conditions y(0) = 1 and y'(0) = 4. Find the solution by using the initial conditions to get linear equations for a and b.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The solution of a certain differential equation is of the form y(t) = ae5t + bet, where a and b are
constants.
The solution has initial conditions y(0) = 1 and y'(0) = 4.
Find the solution by using the initial conditions to get linear equations for a and b.
y(t) =
esc
→
/ c
Oll
O
PA
3
4
5
6
7
8
9
q
W
1000
e
r
t
у
O
a
S
d
g
j
к
VOOQDBhDkKDA
0000 0000
b
1
1
N
2
#
$
%
&
*
(
✔
)
O
4
Transcribed Image Text:The solution of a certain differential equation is of the form y(t) = ae5t + bet, where a and b are constants. The solution has initial conditions y(0) = 1 and y'(0) = 4. Find the solution by using the initial conditions to get linear equations for a and b. y(t) = esc → / c Oll O PA 3 4 5 6 7 8 9 q W 1000 e r t у O a S d g j к VOOQDBhDkKDA 0000 0000 b 1 1 N 2 # $ % & * ( ✔ ) O 4
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