The solution of a certain differential equation is of the form y(t) št = ae + bet, where a and b are constants. The solution has initial conditions y(0) 4 and y'(0) 1. Find the solution by using the initial conditions to get linear equations for a and b. y(t) =

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The solution of a certain differential equation is of the form y(t)
et + best, where a and bare
constants.
The solution has initial conditions y(0) = 4 and y' (0)
1.
Find the solution by using the initial conditions to get linear equations for a and b.
y(t) :
Transcribed Image Text:The solution of a certain differential equation is of the form y(t) et + best, where a and bare constants. The solution has initial conditions y(0) = 4 and y' (0) 1. Find the solution by using the initial conditions to get linear equations for a and b. y(t) :
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