The solution of ODE 5y' + xy = x2 +5

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The solution of ODE
5y' + xy = x2 +5
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n differential equation is5y'+xy=x2+5we need to solve the above equation.
1 equation is:5y'+xy=x2+5which can be written asy'+x5y=x25+1that means, dydx+x5y=x25+1which is indeed a first order linear differential equation.
rating factor of the equation is:l.F=efx5dx=e15[xdx=ex210So, the solution of the given differential equation isyxl.F=fx25+1xl.Fdx+C where Cis integral const
of1dxdxfex210dx=ex210.x-fex210x2x10.xdxfex210dx=xex210-
OdxNow, putting the value of fex210dx in 1, we getyex210=xex210-
Odx+fx25ex210+C=yex210=xex210+C=y=e-x210xex210+c-y=x+Ce-x210Hence, the solution isy=x+Ce-x210
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Transcribed Image Text:1 9:0M O content://org.teleg O Solution obtained by STUDENT SERVICES STUDENT SERVICES or All Answers bartleby Join group : @Bartleby_vipp For All Answers chegg Join group : chegg_So Your Question Answer Question The solution of ODE 5y' + xy = x2 +5 Your Answer n differential equation is5y'+xy=x2+5we need to solve the above equation. 1 equation is:5y'+xy=x2+5which can be written asy'+x5y=x25+1that means, dydx+x5y=x25+1which is indeed a first order linear differential equation. rating factor of the equation is:l.F=efx5dx=e15[xdx=ex210So, the solution of the given differential equation isyxl.F=fx25+1xl.Fdx+C where Cis integral const of1dxdxfex210dx=ex210.x-fex210x2x10.xdxfex210dx=xex210- OdxNow, putting the value of fex210dx in 1, we getyex210=xex210- Odx+fx25ex210+C=yex210=xex210+C=y=e-x210xex210+c-y=x+Ce-x210Hence, the solution isy=x+Ce-x210 العربية الإنجليزية II
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