The solution of the quadratic equation 2x2 - x-14 = 0 is %3D -1t VII1 A. 1t VI13 C. 4 1t VI11 В. -1t VI13 D. 2.

Q: solve using method of undetermined coefficients 2y'+4y=3cos(2t), y(0)=0

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Q: The equation y² = cx is the general solution of

A: We have to find the differential equation.

Q: Find all real solutions of the equation. 3 + 5z + z2 = 0

A: The given equation is 3+5z+z2=0

Q: Solve (D-4) x - y = 0 - 6x + (D+1) Y = 0

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Q: 3 Vx + 2 + 12 = 18

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Q: Solve using the substitution method.7x+4y=2 and x=18-5y

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Q: Solve by the method of substitution. 2. x+2y- 5= 0 4x +y- 6= 0 3. 2x+ 3y = 13 5х - 2y %3D 4 %3D 4x +…

A: 3x-2y-5=0    →14x+3y-52=0   →2 From equation (1), we get 2y=3x-5⇒y=123x-5 Now put y=123x-5 in…

Q: Find the solution to the equation 4x2 + 5x = 2x + 2 -3± y38 -7± y17 8 X = X = 8 а. -3± V41 X = 8. С.…

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Q: Solve x2(y-z) p +y2(z-x)=z2(x-y)

A: value of P given below..

Q: Solve (D - D’-1)(D - D’-2)z = e3x-y

A: Given: D-D'-1D-D'-2z=e3x-y

Q: 5. Solve, using the method of variation of parameters: a²y" – 2ry + 2y = x*e*

A: x2y'' -2xy' +2y =x4ex To solve: Using method of variation of parameters.

Q: The solution of (1 - y ^ 2) * d * x + (1 + x ^ 2) * d * y = 0

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Q: Solve (2Dy + 5)²z = 0

A: We can solve this problem by method of ordinary differential equation

Q: Use the method of undetermined coefficients to solve y''- 4y'+3y = x^2+ 2x-3e^3x.

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Q: Solve for the general solution of (D: - 5D + 6)y = 4e* using method of undetermined coefficients.

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Q: Find all real solutions of the equation. y5 - 8y4 + 4y3 = 0

A: Given y5-8y4+4y3=0y3y2-8y+4=0⇒y3=0and y2-8y+4=0 y3=0⇒y=0 To solve y2-8y+4=0 by quadratic formulaa=1,…

Q: Solve by the substitution method: x + 2y = 0, (x - 1)2 + (y - 1)2 = 5.

A: Given:  x+2y=0                                          ....1x-12+y-12=5…

Q: 11) Solve by Substitution a. b. -4x – 2y =-1 y=-2x – 4 x+3y=-17 -8x + 8y =-24

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Q: Solve for the general solution (D4 – 16)y = x* + x + 1

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Q: 2xyy′ = y2 − 2x3. Find the solution that passes through the point (1, 2).

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Q: Obtain the general solution.  1. (D4 - 5D2 - 6D - 2) y = 0 2. (D5 - 5D4 + 7D3 + D2 - 8D + 4) y=0

A: According to question, Given differential equation, 1. (D4 - 5D2 - 6D - 2) y = 0 2. (D5 - 5D4 + 7D3…

Q: The equation y2 = cx is the general solution of:

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Q: (b)Solve graphically and explain geometrically X1 - 4x2 = 20.1 3x1 + 52x2 = 5.9

A: The given system of equations: x1-4x2=20.1        ...(i) 3x1+52x2=5.9            ...(ii) Putting…

Q: Solve 1- y"- 6y' + 9y 4e Ans. y Ce +c,xex+2x2er

A: Note: Since you have posted multiple independent questions, we will be solving only the first one…

Q: Solve 3x + 2y > 6 graphically.

A: Shaded area below is the graphical solution.

Q: Solve for the particular solution: 1. y^(4)+2y''=2

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Q: C. Solve by the method of elimination. 1. Зу 2x + 3y =13 =D2 2. 3x + 10y = 2 X- 2y = - 6 3. 3x+ 2y =…

A: The elimination method is used to find the solution of algebraic equations. In the elimination…

Q: Solve , (D^3+D^2-4D-4)y = 8x+8+6e^(-x)

A: Given: Solve (D3+D2-4D-4)y=8x+8+6e-x

Q: Solve for t. 4 - 1 - 1 =D4 - 3 -3

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Q: Use the method of separation of variables to solve 2.xyU, +2U¸ =0, U(x,0) = 3e4**

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Q: a. Solve x2 + 2x-y+1%30 and x + y-1=0 using Elimination Method

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Q: Solve using any method. -x- 2y = - 13 - 4x+ 2y=2 A inconsistent

A: Given equation  -x-2y=-13      (1) -4x+2y=2          (2)

Q: Find the general solution (D3-3D2-3D+1)y = 0

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Q: The equation 2x2−6x−9=02x2−6x−9=0 has two solutions. The smaller is ___ , and the larger ___  .

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Q: Solve for the general solution: y' – 5y = x³e*

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Q: Solve the equations by Gaussian elimination: 4x + 6y – 2z = 8 6x + 9y – 3z = 12 -2x - 3y + z = -4

A: Solution using Gaussian elimination is given below

Q: (ii) Solve x(2z - 3y)p + y(3x + z)q + yz + 2xz = 0

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Q: Solve the simultaneous equations y = x + 6 and y = 2x² algebraically and show the result…

A: First equation represents a straight line and second equation represents a parabola symmetric about…

Q: Solve by the substitution method. 2х — 5y %3D 8 x = 4y + 4 (х, у) %3

A: We have to find value of x and y by substitution.

Q: SOLVE 2xyy' = 1 + y² w/ x = 2 and y = 3

A: Solve 2xyy'=1+y2 where x=2 , y=3   dydx=12xy+y22xy       = 12xy+y2xdydx-y2x=12xy-1

Q: Solve by the substitution method 3x + 2y = 4 and 2x + y = 1.

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Q: Use variation of parameters to solve y'' - 7y' +10y= e^2x.

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Q: How to solve this equation y" - 4y" + 2y' - 16y = 4x + 1 using Variation of Parameters.

A: Step:-1 Given that y'''-4y''+2y'-16y=4x+1 For complementary function, The auxiliary equation is…

Q: Solve Using left to right elimination method x-2y-z=0 x-3y+z=1 3x-6y+z=12

A: The given equations are, x-2y-z=0                                                       1x-3y+z=1…

Q: The equation 22x – 5 x 2* +6 = 0 has two solutions. The smaller is and the larger is

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Q: (b) Solve the general solution y' + 2y = x³e–2x AP [4] i. 1-3x2 y' Lx(1-x²). ii. y = 1-x²

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Q: Use the method of undetermined coefficients to find one solution of y" + 3 y – 3 y = (-1x² – 2 x +…

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Q: x  -   y  -  z  =  2 -x  +2y  - 3z  = -5 3x  - 2y  - 7z  =3 solve x, y and z

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Q: y"-4y-60y = 32e2 - 39e-3z +60e4

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.