The solution to the differential equation f(t) is y(t) = f(t) = g(t)us(t), where = y'' – 5y' + 6y g(t) = = — 0
The solution to the differential equation f(t) is y(t) = f(t) = g(t)us(t), where = y'' – 5y' + 6y g(t) = = — 0
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 15CR
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Question
![The solution to the differential equation
=
y'' - 5y' + 6y
is y(t) = f(t) — g(t)us(t), where
f(t)
g(t) =
=
1
10
0 < t < 5
t > 5
9
y(0) = y'(0) = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2323f944-68c6-4ffb-b4bd-7709a3866c17%2Fe72fd9e0-5595-4af6-bdc4-d2a4a581998f%2F6pl62uq_processed.png&w=3840&q=75)
Transcribed Image Text:The solution to the differential equation
=
y'' - 5y' + 6y
is y(t) = f(t) — g(t)us(t), where
f(t)
g(t) =
=
1
10
0 < t < 5
t > 5
9
y(0) = y'(0) = 0
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