The SQL statement below is used to select students with the last name "Smith". What is wrong with the statement? SELECT FirstName FROM Student WHERE LastName = Smith;
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- Given the following SQL statement, which statement is most accurate?SELECT customer# FROM customersJOIN orders USING(customer#)WHERE shipdate-orderdate IN(SELECT MAX(shipdate-orderdate) FROM ordersWHERE shipdate IS NULL);a. The SELECT statement fails and returns an Oracle error message.b. The outer query displays no rows in its results because the subquery passes a NULLvalue to the outer query.c. The customer number is displayed for customers whose orders haven’t yet shipped.d. The customer numbers of all customers who haven’t placed an order are displayedWrite an SQL statement that will insert an order in the orders table with the following data: cutomerID=3, orderDate = current date, shipAmount=20, taxAmount=23.56, shipDate=a week after current date, shipAddressID=3, cardType=2, cardNumber=4123123412341234, cardExpires=05/2024, billingAddressID=3 Write an SQL statement to delete all orders that are created between 2017-06-01 and 2017-06-07.Write a SQL query, which shows a list of all employees last name, their department names and their department city where that department is located from the employees table. If an employee does not belong to a department, then their department number should show as “N/A” and their department city should show up as “No City info Found”. MAKE SURE you have all the employees displayed including the employees who do not have a department.
- By using this table answer this question: Write ONE SQL statement which uses the SUBSTR function (as many times as you need to) to extract the following three words: ‘I’, ‘am’, ‘here’ from the string ‘Where am I?’ and put the three words together using a combination of the CONCAT function and the ||. E.g. The starting string used in the SQL statement is: ‘Where am I?’ The output of the SQL statement after we run it will be: TRANS ---------- I am hereUsing the sample "Solmaris Condo" "database" (just a bunch of tables with a theme) I had you create before this test, write a SQL statement to do the following: List the condo ID, square footage, owner number, service ID, number of estimated hours, and number of spent hours for each service request on which the category number is 4.use oracle sql command line with found or notfound method --- with table Customer(customerNo,costomerName ,gender) Employee (employeeNo,employeeName,job) ,branch(No,Name), category(catNo,catogeryName) ___ 4) Create database package pointOfSal which contain the following A. procedure to add new customer which use validation method checkExistingCustomer using cursor to validate customer name if its not exists before, then add this new customer and generate the customer number automatically using database trigger. B. Method to add new Employee which use validation method checkExistingEmployee using cursor to validate Employee name if its not exists before, then add this Employee and generate the Employee number automatically using database trigger. C. procedure to add new Category which use validation method checkExistingCategory using exception to validate category name if its not exists before, then add this category and generate the category number automatically using database…
- You have the following tables: MANAGERS (MANAGER_ID, LAST_NAME, FIRST_NAME, DEPARTMENT) ACCOUNTS (ACCOUNT_NUMBER, MANAGER_ID, CUST_ID, BALANCE) CUSTOMERS (CUST_ID, LAST_NAME, FIRST_NAME) Write a SQL statement that lists account number, balance, MANAGER’s last name, CUSTOMER ID, and CUSTOMER’s last name for every account in the ACCOUNTS table.This is for SQL. Show a union that uses more than two select statements. The following select statement shows the number of lunches that each employee will attend, but it does not account for Carol Rose or Paula Jacobs because they are not attending any lunches. Modify this statement to show that these two people will not attend any lunches. select a.first_name, a.last_name, count(b.lunch_id) as number_of_lunchesfrom l_employees a inner join l_lunches b on a.employee_id = b.employee_idgroup by a.first_name, a.last_name;Using the Orders database attached write the SQL Statements for the below cases: Get all the orders placed by a specific customer. CustomerID for this customer is MAGAA. My answer here is; select * from tblOrders where CustomerID = 'MAGAA'; Show customers whose ContactTitle is not Sales Associate. Display CustomerID, CompanyName, Contact Name, and ContactTitle Show customers who bought products where the EnglishName includes the string “chocolate”. Display CustomerID, CompanyName, ProductID, ProductName, and EnglishName Show products which were bought by customers from Italy or USA. ”. Display CustomerID, CompanyName, ShipCountry, ProductID, ProductName, and EnglishName Show total price of each product in each order. Note that there is not a column named as total price. You should calculate it and create a column named as TotalPrice. Display OrderID, ProductID, ProductName, UnitPrice, Quantity, Discount, and TotalPrice Show how many products there are in each category and show the…
- Write SQL queries for the following. Display full name of doctors whose first name is other than Tania. Display first name of doctors whose first name contains any of vowels (a,e,i,o,u). Display names of those patients whose name’s second letter is neither ‘a’ nor ‘d’QUESTION 15 Fill the blanks with the suitable PL/SQL statements that correct each of the errors that appear in the given PL/SQL program. declare employeeRecord employee%TYPE; ename varchar2; begin fetch ename, salary inside employeeRecord from employee where enum = 'E8'; DBMS_OUTPUT.PUT_LINE(employee.ename||' '|| employee.Salary); end;The Driver Relationship team realized that maintaining driver IDs is difficult and requested an automatic way of incrementing the value when a new driver is added. You need to make the changes on the table to automatically increment the Driver ID. After the change, you need to insert the following driver: First Name: Nursin Last Name: Yilmaz Driving License ID: 4141447 Start Date: 2019-12-28 Driving License Checked: True Rating: 4.0 THIS IS IN SQL FORMAT FOR CENGAGE MINDTAP, PLEASE HELP I AM STUCK
