The standard form of 3dy-xydx= 3y%e*/3 by Bernoull's equation is: dx A Зе dy xy = 3e**/3,3 dx 3 x- 3e*/3,3 dy y y+yl-x) = 3e*3y3 +y• =y³e **/3 D

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A: Given problem:-

Q: complete

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A: Solution:

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A: Here is the solution

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