The steel framework is used to support the reinforced stone concrete slab that is used for light storage. The slab is 200 mm thick. Determine and sketch the loading that acts along members BE and FED. a- 3m :b- 4m (Note: Use NSCP for minimum loads)
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![The steel framework is used to support the reinforced stone concrete slab that is used for
light storage. The slab is 200 mm thick. Determine and sketch the loading that acts along
members BE and FED.
a- 3m :b- 4m
(Note: Use NSCP for minimum loads)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1884f4a8-980f-4c2c-baf2-08c2771bb90c%2Fde135923-6807-4b0a-9491-ffe9a7a3d774%2Fnb17byo_processed.png&w=3840&q=75)
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- If the beam in Problem 5.5-9 i5 braced at A, B, and C, compute for the unbr Cb aced length AC (same as Cb for unbraced length CB). Do not include the beam weight in the loading. a. Use the unfactored service loads. b. Use factored loads.A beam must be designed to the following specifications: Span length = 35 ft Beam spacing = 10 ft 2-in. deck with 3 in. of lightweight concrete fill (wc=115 pcf) for a total depth of t=5 in. Total weight of deck and slab = 51 psf Construction load = 20 psf Partition load = 20 psf Miscellaneous dead load = 10 psf Live load = 80 psf Fy=50 ksi, fc=4 ksi Assume continuous lateral support and use LRFD. a. Design a noncomposite beam. Compute the total deflection (there is no limit to be checked). b. Design a composite beam and specify the size and number of stud anchors required. Assume one stud at each beam location. Compute the maximum total deflection as follows: 1. Use the transformed section. 2. Use the lower-bound moment of inertia.compute Compute the Euler's Buckling load andGoverning Nominal Compressive strength based on AISC E3-2 or E3-3 (kips)
- 130% v - + 7 Annotate T| Edit Trial expired Unlock Full Version ENGR 263 A A A 4.8 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is a single overhanging beam. Beam AB supports a 500-lb/ft uni- formly distributed floor load on the beam overhang only. Overneia 4 Fr Stee ream (reactions) R. Free-body diagram (negligible weight) Loading conditionThe light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P = 20 KN is applied. Steel E200 Gra A-600mm L-I m 2.0 m 0.6m 1.5 m D. V P-20 KN Aluminum E-70 GPa A-900mm L-1.5 m What is the axial load at aluminum rod in KN?The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P 20 KN is applied. Sheel E200 GPa L-1 m 2.0 m 0.6m 1.5m P-20 KN Aluminum E-70 GPa A=900mm L-1.5 m What is the axial load at steel rod in KN?
- Where is/are the location(s) of the maximum transverese shear stress? A simple I-beam is loaded as shown. 20 mm P KN PKN PKN Į Į -C B с D L/4 m L/4 m Midspan at point C Roller at E at the NA Section B at the top fiber Pin A at point C Midspan at point D Roller E at point D L/4 m L/4 m OE 20 mm 20 mm- 250 mm 150 mm 150 mm AThe light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P= 20 KN is applied. Sleel E-200 GPa A-400mm L1 m 2.0 m 0.6 m 1.5m P-20 KN Aluminum E70 GPa A-900mm L-1.5 m 1. Axial load at steel rod in kN? 2. Axial stress at steel rod in MPa? 3. Axial deformation of aluminum rod in mm? 4. Axial deformation of steel rod in mm? 5. Axial Load at aluminum rod in kN?4-47. The support consists of a solid red brass C83400 copper post surrounded by a 304 stainless steel tube. Before the load is applied the gap between these two parts is 1 mm. Given the dimensions shown, determine the greatest axial load that can be applied to the rigid cap A without causing yielding of any one of the materials. mm 0.25 m SOLUTION 60 mm -10 mm
- 4 - For the beam loading configuration and cross-section shown below, what is the maximum allowable load P given that the maximum allowable stress (in tension and compression) is 120 MPa? PO Р 1.6m PN ż 0.8m 0.8m P80 1.6m Р 30 30 T 10 dimensions in mm beam cross-section (same as problem 3, but inverted)Reinforce an existing simply supported W16 x 36 beam made of A36 steel to carry a service dead load of 0.5 kip/ft and a service live load of 1.1 kip/ft. The beam spans 25 ft and is fully braced by the floor. WELD ALONG THE LENGTH AND ENDS WELD ALONG THE LENGTH AND ENDS A (b) (s) EXISTING BEAM CONTINUOUS PLATE EXISTING BEAM CONTINUOUS PLATE EXISTING BEAMPROBLEM 2: The steel beam loaded below has the built-up cross section as shown. Determine the maximum permissible value of the load w so as not to exceed allowable bending stresses of 110 MPa. -125 mm- w (including beam weight) 20 mm 20 mm 100 mm .-- NA A B - 2 m - 6 m 20 mm FINAL ANSWER: Max. allowable w kN/m
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