Question
Asked Oct 11, 2019
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I'm not sure how to begin the problem. I need to find the tension in cables AB, BC, and AD as well as the height of pole DE. See attached picture for the diagram and given information.

Thank you,

Casey 

The street-lights at A and B are suspended from the two
poles as shown. Each light has a weight of 35 lb .
Suppose that x 4.8 ft. Cable AB is horizontal.
(Figure 1)
Figure
1 of 1
D
18 ft
E
24 ft
10 ft
6 ft
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The street-lights at A and B are suspended from the two poles as shown. Each light has a weight of 35 lb . Suppose that x 4.8 ft. Cable AB is horizontal. (Figure 1) Figure 1 of 1 D 18 ft E 24 ft 10 ft 6 ft

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Expert Answer

Step 1

Draw the free body diagram for light at B.

 

T2
45°
35 lb
Apply vertical force equilibrium condition.
ΣΕ-0
T sin 45° 35 lb = 0
T 49.5 lb
Apply horizontal force equilibrium condition
ΣΗ-0
T,-T cos45° = 0
T-(49.5 lb) cos 45°
0
T, 35 lb
help_outline

Image Transcriptionclose

T2 45° 35 lb Apply vertical force equilibrium condition. ΣΕ-0 T sin 45° 35 lb = 0 T 49.5 lb Apply horizontal force equilibrium condition ΣΗ-0 T,-T cos45° = 0 T-(49.5 lb) cos 45° 0 T, 35 lb

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Step 2

Draw the free body diagram for light at A.

 

T3
T2
35 lb
Apply vertical force equilibrium condition.
ΣΓ-0
T, sin e
35 lb = 0
T sin e 35
Apply horizontal force equilibrium condition
ΣΕ-0
T, cose T 0
T cose 35
1
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T3 T2 35 lb Apply vertical force equilibrium condition. ΣΓ-0 T, sin e 35 lb = 0 T sin e 35 Apply horizontal force equilibrium condition ΣΕ-0 T, cose T 0 T cose 35 1

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Step 3

Determine the ...

T; sin 0
T cose
35
35
tan 0 1
0 =45°
Determine the tension in the cable 3
T, sin 45° 35
Tg 49.5 lb
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T; sin 0 T cose 35 35 tan 0 1 0 =45° Determine the tension in the cable 3 T, sin 45° 35 Tg 49.5 lb

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