The subsonic compressible flow over a cosine-shaped (wavy) wall is illustrated in Fig- ure 2.17. The wavelength and amplitude of the wall are I and h, respectively, as shown in Figure 2.17. The streamlines exhibit the same qualitative shape as the wall, but with diminishing amplitude as distance above the wall increases. Finally, as y → 0, the Streamline at V , M. 2h Figure 2.17 Subsonic compressible flow over a wavy wall; the streamline pattern. streamline becomes straight. Along this straight streamline, the freestream velocity and Mach number are Vo and Mo, respectively. The velocity field in cartesian coordinates is given by h 2n u = Voo 1+ 2лх -2т Ву/е cos (2.35) ве v =-Voh 2л sin and e-27By/e (2.36) B = VT- M where Consider the particular flow that exists for the case where l = 1.0 m, h = 0.01 m, V = 240 m/s, and Mo = 0.7. Also, consider a fluid element of fixed mass moving along a streamline in the flow field. The fluid element passes through the point (x/E, y/€) = (4, 1). At this point, calculate the time rate of change of the volume of the fluid element, per unit volume.
The subsonic compressible flow over a cosine-shaped (wavy) wall is illustrated in Fig- ure 2.17. The wavelength and amplitude of the wall are I and h, respectively, as shown in Figure 2.17. The streamlines exhibit the same qualitative shape as the wall, but with diminishing amplitude as distance above the wall increases. Finally, as y → 0, the Streamline at V , M. 2h Figure 2.17 Subsonic compressible flow over a wavy wall; the streamline pattern. streamline becomes straight. Along this straight streamline, the freestream velocity and Mach number are Vo and Mo, respectively. The velocity field in cartesian coordinates is given by h 2n u = Voo 1+ 2лх -2т Ву/е cos (2.35) ве v =-Voh 2л sin and e-27By/e (2.36) B = VT- M where Consider the particular flow that exists for the case where l = 1.0 m, h = 0.01 m, V = 240 m/s, and Mo = 0.7. Also, consider a fluid element of fixed mass moving along a streamline in the flow field. The fluid element passes through the point (x/E, y/€) = (4, 1). At this point, calculate the time rate of change of the volume of the fluid element, per unit volume.
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images