The subspace W={(0 -b); a, b ER} has the basis set :-a aSelect one:0 0O a. S={(), (-1 10 00 0O b. S= {(1 10 10 10 1O c. S= {()}1 0-1O d. S= {(-1 1

For a set to be a basis of a subspace. i) it must be independent. ii) it should generate the…

Answered: The subspace W={( 0 -b ); a, b E R} has…

The subspace W={( 0 -b ); a, b E R} has the basis set : —а а Select one: 0 0 a. S={(,), 1 0 0 0 0 O b. S = {( 0 1 0 1 0 1 O c.S={)} 1 0 0 -1 O d. S={( ,")» -1 1

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter4: Vector Spaces

Section4.CR: Review Exercises

Problem 26CR

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Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.

Question

The subspace W={(
0 -b
); a, b ER} has the basis set :
-a a
Select one:
0 0
O a. S={(
), (
-1 1
0 0
0 0
O b. S= {(
1 1
0 1
0 1
0 1
O c. S= {(
)}
1 0
-1
O d. S= {(
-1 1

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