The sum of the lengths of the two diagonals of a parallelogram is 18 m. One diagonal is 2 meters longer than the other. The area of the parallelogram is 20 square meters. If the shorter diagonal is increased by 10 cm and the longer diagonal is decreased by 15 cm, what must be the approximate increase or decrease of the acute angle (degrees) between the diagonals so that the approximate change in area will not exceed 4 square meters? Use differentials. Change in =

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