Given the power series n=0 0 6n || 200+ 11/1/2 6 + 816 + O + 62 + 2x 6² x3 d xn d x * £ £ € - ( ¹ + 3 + 2 + 3 + +-) Find x³ 1+ dx 6n dx 6 n=0 62 63 64 by differentiating term by term. Write the first 5 terms below, simplifying any powers of -1. 63 + Jo... Write the series compactly using summation notation (if the series alternates, include the alternator separately): 64 + + 3r² 63 14 n=1 (Notice that since the constant term was dropped, we start the summation at n = 1.) Find the interval of convergence for the new series.

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