The system of equations Kx + 2y – z = 1, (K – 1)y – 2z = 2 and (K+ 2)z = 3 will have a unique solution if K = (A) 0 (B) 1 (C) – 2 (D) –1

Algebra and Trigonometry (MindTap Course List)
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Author:James Stewart, Lothar Redlin, Saleem Watson
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Chapter10: Systems Of Equations And Inequalities
Section10.CR: Chapter Review
Problem 1CC
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The system of equations Kx + 2y – z = 1, (K – 1)y – 2z = 2 and
(K+ 2)z = 3 will have a unique solution if K =
(A) 0
(B) 1
(C) – 2
(D)–1
Transcribed Image Text:The system of equations Kx + 2y – z = 1, (K – 1)y – 2z = 2 and (K+ 2)z = 3 will have a unique solution if K = (A) 0 (B) 1 (C) – 2 (D)–1
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