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The total volume of the water tank used in the equipment is 0.02 m3", and the water is heated through the heating rod. The efficiency of the water circulator 40W is 40%, and the remaining energy is released as heat. Given that the heat lost in the entire area in contact with the outside is

The total volume of the water tank used in the equipment is 0.02 m3", and the water is heated through the heating rod. The efficiency of the water circulator 40W is 40%, and the remaining energy is released as heat. Given that the heat lost in the entire area in contact with the outside is

Refrigeration and Air Conditioning Technology (MindTap Course List)
Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter24: Expansion Devices
Section: Chapter Questions
Problem 8RQ: The TXV responds to an increased heat load by A. decreasing refrigerant flow. B. keeping refrigerant...
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The total volume of the water tank used in the equipment is 0.02 m3", and the water is heated through the heating rod. The efficiency of the water circulator 40W is 40%, and the remaining energy is released as heat. Given that the heat lost in the entire area in contact with the outside is KI(T-Ta)dT, find the following. O 25 °C → 30 °C. 2 30 °C → 35 °C (C.=4.184J/ml-C, Ta=20 °C. K = 10 J/s-C) (1) Energy balance: equation (2) Total energy used by Heating rod (J)
Transcribed Image Text:The total volume of the water tank used in the equipment is 0.02 m3", and the water is heated through the heating rod. The efficiency of the water circulator 40W is 40%, and the remaining energy is released as heat. Given that the heat lost in the entire area in contact with the outside is KI(T-Ta)dT, find the following. O 25 °C → 30 °C. 2 30 °C → 35 °C (C.=4.184J/ml-C, Ta=20 °C. K = 10 J/s-C) (1) Energy balance: equation (2) Total energy used by Heating rod (J)
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