The turning-moment diagram for an engine consists of two isosceles triangles each with a height equivalent to a torque of 16kNm. The bases of the triangles lie between ? = 0 ? and ? = 180 , and ? = 180? and ? = 360? respectively. If the engine is to rotate with a mean speed of 130 rpm, calculate the following: the mass of the flywheel having a radius of gyration 1.1m to restrict the fluctuation of speed to +1.5% of the mean speed.
The turning-moment diagram for an engine consists of two isosceles triangles each with a height equivalent to a torque of 16kNm. The bases of the triangles lie between ? = 0 ? and ? = 180 , and ? = 180? and ? = 360? respectively. If the engine is to rotate with a mean speed of 130 rpm, calculate the following: the mass of the flywheel having a radius of gyration 1.1m to restrict the fluctuation of speed to +1.5% of the mean speed.
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter8: Centroids And Distributed Loads
Section: Chapter Questions
Problem 8.73P
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The turning-moment diagram for an engine consists of two isosceles triangles each with a height equivalent to a torque of 16kNm. The bases of the triangles lie between ? = 0 ? and ? = 180 , and ? = 180? and ? = 360? respectively.
If the engine is to rotate with a mean speed of 130 rpm, calculate the following:
the mass of the flywheel having a radius of gyration 1.1m to restrict the fluctuation of speed to +1.5% of the mean speed.
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