The Ultimate strength of the material * is
Q: n kn
A: given: ratio of linear strain and laterial strain known as?
Q: Define hydrostatic stress state.
A: Solution: It is defined as the state in which stresses of the same magnitude and direction are…
Q: As the temperature increases the modulus of elasticity will increase. True or false?
A: The Modulus of elasticity connects the stress and strain developed in the material due to the…
Q: _____ is an example for indirect stress Select one: a. Shear b. Bending c. Tensile d. Compression
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Q: As the temperature increases, the modulus of elasticity will increase.True or false?
A: Elasticity is the ability of a deformed body to regain its original shape after load on the body is…
Q: Define stress and strain . Mention its unit
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Q: A 4ft long rod with a 0.29 inch diameter is subjected to a 10,130lb tensile load. What is the…
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Q: 2- Draw Shear Stress vs. Strain Diagram for steel specimen
A: To draw stress vs. strain diagram for steel specimen
Q: 1. Plot the stress'strain diagram for the material. 1. Use the graph to calculate:
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Q: ) A- What is fatigue strength?
A: QUESTION : WHAT IS FATIGUE STRENGTH ? ANSWER:-
Q: Hot hardness means that the material will lose its hardness at high temperature. True or false and…
A: The hardness of a material is associated with the strength of the material. This is associated with…
Q: Calculation of main stresses and directions;
A: The Principal stresses are the maximum and minimum normal and shear stress which occurs on a plane…
Q: If cross sectional area of a square bar is increased 5 times, keeping same force then tensile stress…
A: If cross sectional area of a square bar is increased 5 times, keeping same force then tensile stress…
Q: If the area under the stress and strain curve is more then it is concluded that the material has…
A: The area under stress - strain curve represents the energy required or stored in the material before…
Q: 5) Steel stress not reaching yield point is directly proportional to strain. True False
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Q: What is the Average Compressive Stress?
A: Forces acting perpendicular to the cross section of the body are normal forces. They can be either…
Q: a. Define axial strain
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Q: B. Compare between ductile and brittle ?material with stress-strain diagram
A: Ductile materials are those which can be easily drawn out into wires. Many of metals are best…
Q: . What is the longitudinal stress developed in
A: To find Longitudinal stress
Q: Q2. For the following materials define its applications and the reason for the application series…
A: For the following materials define it's applications and the reasons for the applications
Q: The ability of a material that undergoes some degree of permanent deformation without failure is…
A: False.
Q: 1 kN load is applied to the plates in shear, what is
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Q: The dilatation is a measure of volumetric strain.True or false?
A: volumetric strain-It is defined as the ratio of the change in volume to the original volume.…
Q: 2 kN 50 mm 5 kN• m D 80 mm B C 1.0 m 1.0 m 1.0 m
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Q: e maximum allowable load
A: To find Maximum allowed load
Q: The ratio of decrease in length to the original length is known as compressive strain. Select one:…
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Q: What is an expression of true stress? А. Load / final area В. Load / initial area C. O Load /…
A: As per given question What is the express true stress.
Q: The ratio of increase in length to the original length is known as tensile strain. Select one: True…
A: Starin: Tensile strain is defined as the ratio of increase in length to the original length.
Q: Determine the final cross-sectional area for a tensile specimen that has 31 mm2 as the initial area…
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Q: (a) Maximum tensile flexural stress (Indicate where it occurs what section and where in the…
A: Given that , w=5kN/mP=15.11kN
Q: - 2- 45 100lbs/ft 300lb 30 200lbs
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Q: Engineering stress and strain are calculated using the actual cross-sectional area and length of the…
A: Engineering stress and strain are calculated using the actual cross-sectional area and length of the…
Q: a) Draw stress-strain curves for mild steel and TOR steel b) Proportional Limit or Elastic Limit
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Q: Draw V & M diagram
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Q: 20 bar with te angles 30° anc
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Q: At room temperature, mild steel is a ductile material. True or false?
A: At room temperature the mild steel is ductile material. A ductile material shows liner relationship…
Q: Select the appropriate Stress -Strain plot which has the highest ultimate tensile strength from the…
A: Option a is correct.
Q: The ratio of original length to the increase in length is known as tensile strain. Select one: True
A: strain: the ratio of increase in length to the original length is called strain or tensile strain.
Q: Which of the following stress strain curve shows an elastic behaviour to very high strain rate O a.…
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Q: Diameter of gauge length =19mm , Gauge length =100 mm Diameter at fracture = 16.49 mm , Gauge length…
A: Load(KN) Extension(mm) 0 0 15 0.05 30 0.094 40 0.127 50 0.157 55 1.778 60 2.79 65…
Q: As a beam becomes longer, the strain energy due to bending becomes much larger than the strain…
A: It is true to note that the strain energy because of bending becomes larger than due to shear.
Q: Draw two schematic graphs using pencil showing a typical stress-strain curve for aluminum. The first…
A: Draw two schematic graphs using pencil showing a typical stress-strain curve for aluminum. The…
Q: What is the method used forfinding the Internal Resultant Loadings?
A: When an external load is applied to a beam, an internal reaction force is generated across the…
Q: Question 5: Based on the stress-strain diagram for a material shown here, find the followings: Yield…
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Q: Which of the following statement is true? a. Statically determinate structures are more stable (or…
A: Answer 1: The statically determinate structures are less stable as compared to the indeterminate…
Q: 1. Define ultimmate tensile strength
A: As per our guidelines we are supposed to solve only one question if multiple questions are asked .…
Q: 5. A member which does not regain its original shape after removal of the load producing deformation…
A: Let us first understand the meaning of each option. If the body does not allow any deformation under…
Q: What is the reaction of shear stress on the cross-section?
A: Shear stress The stress created due to the load applied in the parallel direction of the…
Q: ehavior of tensingrity bridge
A: Given Data : Tensegrity bridge
Q: between direct stress and bending stress.
A: To define: Distinguish between direct stress and bending stress
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- Determine the strain energy per unit volume (units of psi) and the strain energy per unit weight (units of in ) that can be stored in each or the materials listed in the accompanying table, assuming that the material is stressed to the proportional limit. DATA FOR PROBLEM 2.7-5 Material Weight Density (lb/in3) Modulus of Elasticity (ksi) Proportional Limit (psi) Mild sleel 0.284 30,000 36,000 Tool steel 0.284 30,000 75,000 Aluminum 0.0984 10,500 60,000 Rubber (soft) 0.0405 0.300 300(a) Solve part (a) of the preceding problem if the pressure is 8.5 psi, the diameter is 10 in., the wall thickness is 0,05 in., the modulus of elasticity is 200 psi, and Poisson's ratio is 0.48. (b) If the strain must be limited to 1.01, find the maximum acceptable inflation pressureDuring stress-strain test, the unit deformation at a stress of 35 MPa was observed to be 167 x 10^-6 m/m and at a stress of 140 MPa it was 667 x 10^-6. If the proportional limit was 200 MPa, what is the modulus of Elasticity (GPa)? What is the strain corresponding to a stress of 80 MPa?
- For some metal alloy, a true stress 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 418 MPa (60630 psi) is applied if the original length is 500 mm (19.69in) ? Assume a value of 0.22 for the strain- hardening exponent, nDraw the tensile curves of the following materials, taking into account the appropriate elongation at break, modulus of elasticity and tensile stress, on the side stress-strain graph. a)Low carbon steel (Ecelik=200Gpa),(Syield=300MPa),(Stensile=400MPa) b)High carbon steel (Esteel=200GPa),(Stensile=700MPa) c)Aluminum (Ealuminum=70GPa), (Syield=200MPa),(Stensile=300MPa) d)Cast iron (Ecast iron=120GPa),(Stensile=200MPa)A Copper specimen of circular cross-section is subjected to a tensile test. The data obtained are: Length of Specimen = 329 mm; Diameter of Specimen = 39 mm; Load at Yield Point = 130 kN; Maximum Load = 219 kN; Load at fracture = 118kN Determine the following: 1) Find initial area of the test specimen 2) Yield Stress 3) Ultimate Stress 4) Fracture stress 5) Find the strain for 0.058mm elongation.
- A Copper specimen of circular cross-section is subjected to a tensile test. The data obtainedare:Length of Specimen = 329 mm;Diameter of Specimen = 39 mm;Load at Yield Point = 130 kN;Maximum Load = 219 kN;Load at fracture = 118kNDetermine the following:1) Find initial area of the test specimen2) Yield Stress3) Ultimate Stress4) Fracture stress5) Find the strain for 0.058mm elongation.6) Mark Yield stress, Ultimate stress and Fracture stress on a Stress-Strain diagram.You are given a square rod of 6061-T6 aluminum (cross-section = 4mm X 4mm, length = 2.3m). The material has a Young’s modulus of 72 GPa. If a compressive load of 3 kN is applied parallel to the 2.3m dimension, what is the resulting engineering normal strain?Stress Strain-Behavior A specimen of aluminum having a rectangular cross section 10 mm × 12.7 mm(0.4 in.× 0.5 in. ) is pulled in tension with 35,500 N (8000 lbf) force, producing onlyelastic deformation. Calculate the resulting strain.
- A specimen of aluminum having a rectangular cross section 9.6 mm × 13.0 mm (0.3780 in. × 0.5118 in.) is pulled in tension with 35800 N (8048 lbf) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 × 106 psi). Calculate the resulting strain. Enter your answer in accordance to the question statementstress-strain behavior for the brass specimen shown in Figure 6.12, determine the following: (a) The modulus of elasticity (b) The yield strength at a strain offset of 0.002 (c) The maximum load that can be sustained by a cylindrical specimen hav- ing an original diameter of 12.8 mm (0.505 in.) (d) The change in length of a specimen originally 250 mm (10 in.) long that is subjected to a tensile stress of 345 MPa (50,000 psi)1. In the nominal stress-strain diagram (Figure 1), write down the names and meanings of points 1, 2, 3, and 4.2. Explain how to find the 0.2% offset yield strength, and explain the% elongation and% reduction in cross-sectional area.3. After explaining the difference between the true stress/strain and the nominal stress/strain, show the true stress-strain diagram for the nominal stress-strain diagram (Figure 1) to correspond points 1, 2, 3, and 4.