SOLVE USING MATLAB CODES The value of fxe dx by the using one-segment trapezoidal rule is most nearly0.2(A) 11.672(B) 11.807(C) 20.099(D) 24.119SolutionThe correct answer is (C).f(a)+ f(b)kdx2wherea = 0.2b = 0.2f(x) = xe*f(0.2) = 0.2e02= 0.24428f(2.2) = 2.2e= 19.855220.24428 +19.855fxe'dx = (2.2-0.2)20.2= 2x10.050%3D= 20.099

Answered: The value of fxe dx by the using…

The value of fxe dx by the using one-segment trapezoidal rule is most nearly 02 (A) 11.672 (B) 11.807 (C) 20.099 (D) 24.119

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

SOLVE USING MATLAB CODES

The value of fxe dx by the using one-segment trapezoidal rule is most nearly
0.2
(A) 11.672
(B) 11.807
(C) 20.099
(D) 24.119
Solution
The correct answer is (C).
f(a)+ f(b)
kdx
2
where
a = 0.2
b = 0.2
f(x) = xe*
f(0.2) = 0.2e02
= 0.24428
f(2.2) = 2.2e
= 19.855
22
0.24428 +19.855
fxe'dx = (2.2-0.2)
2
0.2
= 2x10.050
%3D
= 20.099

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