The vapor pressures of heptane (substance 1) and octane (substance 2) are as follows: Temp(°C) vapor pressure heptane(mmHg) vapor pressure octane (mmHg) 98.5 760 342 100 795 354 110 1047 482 120 1367 646 126 1560 760 Assuming the above liquid mixture obeys Raoult's law:
The vapor pressures of heptane (substance 1) and octane (substance 2) are as follows: Temp(°C) vapor pressure heptane(mmHg) vapor pressure octane (mmHg) 98.5 760 342 100 795 354 110 1047 482 120 1367 646 126 1560 760 Assuming the above liquid mixture obeys Raoult's law:
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The vapor pressures of heptane (substance 1) and octane (substance 2) are as follows:
Temp(°C) | vapor pressure heptane(mmHg) | vapor pressure octane (mmHg) |
98.5 | 760 | 342 |
100 | 795 | 354 |
110 | 1047 | 482 |
120 | 1367 | 646 |
126 | 1560 | 760 |
Assuming the above liquid mixture obeys Raoult's law:
- Sketch the diagram of the boiling point for a total vapor pressure of 760 mm Hg.
- Determine the bubble point (bubble temp) if x 1 = 0.3 at 760 mm Hg.
- Determine the dew point if y1 = 0.3 at 760 mm Hg
- Make a P-xy equilibrium diagram at 110° C
- Graphically calculate the bubble pressure if x1 = 0.6 at 110° C
- Graphically calculate the dew pressure if y1 = 0.6 at 110 o C
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