The velocity function is v(t) = t2 – 5t + 4 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [-1,5]. displacement = distance traveled =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I need some help with the couple of questions below. I know about the rules, but I will only upvote if both are answered. I get if you don't want to answer both but I know some people will. So, just save us both time. I'm not going to upvote if both aren't answered so you might as well safe yourself the time of doing the problem. I'm not trying to be rude, I'm just a broke college kid who can't afford more questions & is genuinely confused. Thank you in advance. 

The velocity function is v(t) = t² – 5t + 4 for
a particle moving along a line. Find the
displacement and the distance traveled by the
particle during the time interval [-1, 5].
-
displacement =
distance traveled =
Transcribed Image Text:The velocity function is v(t) = t² – 5t + 4 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [-1, 5]. - displacement = distance traveled =
Evaluate
f(x) dx, where
-T< x < 0
f(x)
17 sin(x), 0 < x < T.
TT
f(x) dx :
-T
Transcribed Image Text:Evaluate f(x) dx, where -T< x < 0 f(x) 17 sin(x), 0 < x < T. TT f(x) dx : -T
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