The velocity of a particle moving in the x-y plane is given by (7.24i + 6.04j) m/s at time t = 4.27 s. Its average acceleration during the next 0.022 s is (2.3i + 4.0j) m/s?. Determine the velocity v of the particle att = 4.292 s and the angle e between the average- acceleration vector and the velocity vector at t = 4.292 s. Answers: v = ( i i+ i j) m/s e = i
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