The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law,V = IR, to find how the current I is changing at the moment when R = 402 S2, I = 0.02 A, dv/dt = -0.01 V/s, and dR/dt = 0.05 2/s. (Round your answer to six decimal places.) A/s

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.5: Differentials: Linear Approximation
Problem 14E: Use the differential to approximate each quantity. Then use a calculator to approximate the...
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The voltage Vin a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the
resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 402 , I = 0.02 A,
dv/dt = -0.01 V/s, and dR/dt = 0.05 /s. (Round your answer to six decimal places.)
A/s
Transcribed Image Text:The voltage Vin a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 402 , I = 0.02 A, dv/dt = -0.01 V/s, and dR/dt = 0.05 /s. (Round your answer to six decimal places.) A/s
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