I need help with the last three parts. I am not allowed to use Excel or a Ti-84 calculator. I need to work these by hand, however, I cannot figure them out. The waiting time to get food at a fast-food restaurant is 4.5 minutes on average with standard deviation of 2 munutes. Suppose that a sample of 45 customers is randomlyselected.A. What are the mean and standard deviation of the sample mean waiting time of 45 customers?Mean: =Standard Deviation (standard error of the mean)4.5= 0.29814minutes Round standard error to 5 decimal places.B. What is the probability that the average waiting time of 45 customers is less than 4.3 minutes?Round to 4 decimal places.C. What is the probability that the average waiting time of 45 customers is greater than 4.7 minutes?Round to 4 decimal places.D. What is the probability that the average waiting time of 45 customers is between 4.3 and 4.7 minutes?Round to 4 decimal places.Answer:Answer:minutesAnswer:

Given that, μ=4.5σ=2n=45 (A) The mean of the sampling distribution of sample mean is,

The waiting time to get food at a fast-food restaurant is 4.5 minutes on average with standard deviation of 2 munutes. Suppose that a sample of 45 customers is randoml selected. A. What are the mean and standard deviation of the sample mean waiting time of 45 customers? Mean = 4.5 Standard Deviation (standard error of the mean) = 0.29814 minutes Round standard error to 5 decimal places. B. What is the probability that the average waiting time of 45 customers is less than 4.3 minutes? Round to 4 decimal places. Answer: minutes C. What is the probability that the average waiting time of 45 customers is greater than 4.7 minutes? Round to 4 decimal places. D. What is the probability that the average waiting time of 45 customers is between 4.3 and 4.7 minutes? Round to 4 decimal places. Answer: Answer:

The waiting time to get food at a fast-food restaurant is 4.5 minutes on average with standard deviation of 2 munutes. Suppose that a sample of 45 customers is randoml selected. A. What are the mean and standard deviation of the sample mean waiting time of 45 customers? Mean = 4.5 Standard Deviation (standard error of the mean) = 0.29814 minutes Round standard error to 5 decimal places. B. What is the probability that the average waiting time of 45 customers is less than 4.3 minutes? Round to 4 decimal places. Answer: minutes C. What is the probability that the average waiting time of 45 customers is greater than 4.7 minutes? Round to 4 decimal places. D. What is the probability that the average waiting time of 45 customers is between 4.3 and 4.7 minutes? Round to 4 decimal places. Answer: Answer:

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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I need help with the last three parts. I am not allowed to use Excel or a Ti-84 calculator. I need to work these by hand, however, I cannot figure them out.