Please answer the following questions. ASAP thanks! Question 10Sieve analysis was performed in the laboratory. It was found out thatthe soil has a relatively large value of Cu. What does this indicate?O The soil is well-graded.We have a gap-graded soil.None of the AboveThe soil is poorly-graded.Question 11How do you interpret the particle size distribution of a soil sampleshown below without computing for the uniformity coefficient andcoefficient of curvature?O The soil is uniformly-graded.The soil is gap-graded.The soil is well-graded.O None of the AboveQuestion 12This corresponds to the water content at which soil changes from aliquid state to a plastic state.O None of the AboveLiquid LimitShrinkage LimitO Plastic Limit Question 7The weight of the dry soil per unit volume is known asBulk Unit WeightSaturated Unit WeightDry Unit WeightEffective Unit WeightQuestion 8The hydrometer test is used to determine the size rangeof particles of soil with diameters smaller than mm.0.075 mm0.750 mm0.020 mmNone of the Above0.200 mmQuestion 9The of a soil material indicates how much of the voidspaces is filled up with water.Bulk Unit WeightPorosityDegree of SaturationWater Content

7. The weight of the dry soil per unit volume is known as Dry Unit Weight Bulk Unit Weight…

The weight of the dry soil per unit volume is known as Bulk Unit Weight Saturated Unit Weight O Dry Unit Weight Effective Unit Weight Question 8 The hydrometer test is used to determine the size range of particles of soil with diameters smaller than mm. 0.075 mm 0.750 mm O 0.020 mm None of the Above 0.200 mm Question 9 Theof a soil material indicates how much of the void spaces is filled up with water. Bulk Unit Weight Porosity Degree of Saturation O Water Content

The weight of the dry soil per unit volume is known as Bulk Unit Weight Saturated Unit Weight O Dry Unit Weight Effective Unit Weight Question 8 The hydrometer test is used to determine the size range of particles of soil with diameters smaller than mm. 0.075 mm 0.750 mm O 0.020 mm None of the Above 0.200 mm Question 9 Theof a soil material indicates how much of the void spaces is filled up with water. Bulk Unit Weight Porosity Degree of Saturation O Water Content

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Soil Deposits-origin, Grain-size, And Shape

Section: Chapter Questions

Problem 2.4P: For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Calculate the uniformity coefficient...

See similar textbooks

Similar questions

The particle size characteristics of diameter (mm) and retained mass (g) of a soil are: For 4.75 mm retained 0 g; 2.0mm retained 40g; 0.85mm retained 60g; 0.425mm retained 89g; 0.25mm retained 140g; 0.18mm retained 122g; 0.125mm retained 210g; 0.075 mm retained 56 g and at the bottom retained with 12 g. Determine the percentages of gravel, sand, silt and clay.
Soil samples A and B have void ratios of 0.5 and 0.7 respectively. If 1.5 m³ of soil sample A and 1.7 m³ of soil sample B are mixed to form sample Chaving a volume of 3.2 m³, which one of the following correctly represents the porosity of sample C? ⚫ (a) 0.375 (b) 0.60 (c) 1.66 (d) 2.66 [CSE: 2002]
For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the dry density of soil in slug/ft3. Note p of water= 1.94 slug/ft3 a. 2.85 b. 3.6 c. 2.95 d. 3.8
2. Sand cone equipment is used to perform a field density test on a compacted earth fill. Sand is used in the cone and is known to have a bulk density of 15.74 kN/m3 . Soil sample dug from test hole, (wet weight) = 20.601 N Dry weight of soil sample = 17.926 N Weight of sand (sand cone) to fill test hole = 16.503 N Determine the in-place dry density of the tested soil (Ans: 17.57 kN/m3) Determine the water content (Ans: 15%) Compute the percentage of compaction of the tested soil if the laboratory moisture-density curve indicates a dry density of 18.10 kN/m3 and an optimum moisture content of 13%. (Ans: 97.07%)
For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Calculate the uniformity coefficient and the coefficient of gradation of the soil. 2.4 Repeat Problem 2.3 for the following: D10 = 0.24 mm D30 = 0.82 mm D60 = 1.81 mm
1. If a soil sample has a dry unit weight of 19.5 KN/m3, moisture content of 8%and a specific gravity of solids particles is 2.67. Calculate the following:a) The void ratio.b) Moisture and saturated unit weight.c) The mass of water to be added to cubic meter of soil to reach 80% saturation.d) The volume of solids particles when the mass of water is 25 grams for saturation Ans:a.) 0.343b.) 12.85% and 22 KN/m3 c.) 44.8 kgd.) 72.84 cm3 Please show your solutions and the final answers are provided above.
A pycnometer test for the determination of water content of a soil sample having the Gs=2.70, yielded following data: Weight of moist soil=230.75g Weight of Pycnometer full of water=2965.20g Weight of Pycnometer+soil+water =3092.85g
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34 d. 88.41
A soil sample has a void ratio of 0.65, dry unit weight of 14.50 KN/m3, and water content of 8 percent. 1. Solve the Specific gravity of the soil sample. A. 2.78 B. 3.16 C. 2.44 D. 3.27 2. What is the moist unit weight in KN/m3when the degree of saturation is 54%? A. 59 B. 21.06 C. 18.37 D. 19.55 3. Determine the volume of voids if the total volume of the soil is 3.67 cu.m A. 43 B. 2.39 C. 1.82 D. 3.16
The water content of a soil sample is 5.8%. The dry unit weight is = 16.2 kN/m3 and Gs = 2.7. How much isthe void space in a soil sample most nearly made up of water?
Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30, PL = 10) ? Use this given M=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 gM=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 g Sieve No. Opening Size (mm) Mass retained (g) %Mass retained=MiM×100=MiM×100 %Cumulative mass retained % Finer 4 4.750 28 =28617×100%=4.54%=28617×100%=4.54% 4.54 95.46 10 2.0 42 =42617×100%=6.81%=42617×100%=6.81% 11.35 88.65 20 0.850 48 =48617×100%=7.78%=48617×100%=7.78% 19.13 80.87 40 0.425 128 =128617×100%=20.74%=128617×100%=20.74% 39.87 60.13 60 0.250 221 =221617×100%=35.82%=221617×100%=35.82% 75.69 24.31 100 0.150 86 =86617×100%=13.94%=86617×100%=13.94% 89.63 10.37 200 0.075 40 =40617×100%=6.48%=40617×100%=6.48% 96.11 3.89 Pan 24 =24617×100%=3.89%=24617×100%=3.89% 100 0 Now, to plot the GSD curve, the % finer is kept on the vertical axis and the opening size are kept on the horizontal axis -…
2. Sand cone equipment is used to perform a field density test on a compacted earth fill. Sand is used in the cone and is known to have a bulk density of 15.74 kN/ . Soil sample dug from test hole, (wet weight) = 20.601 N Dry weight of soil sample = 17.926 N Weight of sand (sand cone) to fill test hole = 16.503 N Determine the in-place dry density of the tested soil (Ans: 17.57 kN/ ) Determine the water content (Ans: 15%) Compute the percentage of compaction of the tested soil if the laboratory moisture-density curve indicates a dry density of 18.10 kN and an optimum moisture content of 13%. (Ans: 97.07%)