The zeros in the given matrix make its characteristic polynomial easy to calculate. Find the general solution of x' = Ax. 2 0 0 0 - 14 -5 12 -6 A = 0 0 5 0 0 -14 - -2 ... x(t) = 0
The zeros in the given matrix make its characteristic polynomial easy to calculate. Find the general solution of x' = Ax. 2 0 0 0 - 14 -5 12 -6 A = 0 0 5 0 0 -14 - -2 ... x(t) = 0
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.CR: Review Exercises
Problem 15CR: For what values of a does the matrix A=[01a1] have the characteristics below? a A has eigenvalue of...
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