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Theorem 16. Show that if t: V→ V is a self duct space V, then s* is is self-adjoint for every lin nvertible and ts is self adioint, then t is seif adio

Theorem 16. Show that if t: V→ V is a self duct space V, then s* is is self-adjoint for every lin nvertible and ts is self adioint, then t is seif adio

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.5: The Kernel And Range Of A Linear Transformation
Problem 6EQ
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Theorem 16. Show that if t: V→ V is a self adjoint linear transformation on an inner product space V, then s* is is self-adjoini for every linear transformation s: V- V Furiher if's is invertible and s* ts is self adjoint, then t is seif adjoint.
Transcribed Image Text:Theorem 16. Show that if t: V→ V is a self adjoint linear transformation on an inner product space V, then s* is is self-adjoini for every linear transformation s: V- V Furiher if's is invertible and s* ts is self adjoint, then t is seif adjoint.
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