Theorem 17. Suppose f is continuous at a and g is continuous at f(a). Then gof is continuous at a. [Note that (go f)(x) = g(f(x))./ Problem 116. Prove Theorem 17 (a) Using the definition of continuity. (b) Using Theorem 15, The obe build tinuo funotione from

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#116 part b
We have =0, but lim
4:38
A inst-fs-iad-prod.inscloudgate.net
Note that Theorem3 of ChapterI will probably help here.]
116 of 220
Jequences and Continuity
There is an alternative way to prove that the function
D(z) = , if z is rational
(0, if r is irrational
is not continuous at a + 0. We will examine this by looking at the relationship
between our definitions of convergence and continuity. The two ideas are actu-
ally quite closely connected, as illustrated by the following very useful theorem.
Theorem 15. The function f is continuous at a if and only if ƒ satisfies the
following property:
V sequences (r,,), if lim r, = a then lim f(r,) = f(a).
n
Theorem 15 says that in order for f to be continuous, it is necessary and
sufficient that any sequence (zn) converging to a must force the sequence (f(zn))
to converge to f(a). A picture of this situation is below though, as always, the
formal proof will not rely on the diagram.
CONTINUITY: WHAT IT ISN'T AND WHAT IT Is
111
This theorem is especially useful for showing that a function f is not con-
tinuous at a point a; all we need to do is exhibit a sequence (r,) oconverging
to a such that the sequence lim, f(rn) does not converge to f(a). Let's
demonstrate this idea before we tackle the proof of Theorem 15,
Example 12. Use Theorem 15 to prove that
(z) =
10,
if z=0
is not continuous at 0.
Proof: First notice that f can be written as
if r>0
S(z) = {-1 if x <0
if x = 0
To show that f is not continuous at 0, all we need to do is create a single
sequence (r,) which converges to 0, but for which the sequence (f (xn)) does not
converge to f(0) = 0. For a function like this one, just about any sequence will
do, but let's use (1), just because it is an old familiar friend.
()-
We have lim
-
= 0, but lim f
= lim 1=1#0 = f(0). Thus by
Theorem 15 f is not continuous at 0.
Transcribed Image Text:We have =0, but lim 4:38 A inst-fs-iad-prod.inscloudgate.net Note that Theorem3 of ChapterI will probably help here.] 116 of 220 Jequences and Continuity There is an alternative way to prove that the function D(z) = , if z is rational (0, if r is irrational is not continuous at a + 0. We will examine this by looking at the relationship between our definitions of convergence and continuity. The two ideas are actu- ally quite closely connected, as illustrated by the following very useful theorem. Theorem 15. The function f is continuous at a if and only if ƒ satisfies the following property: V sequences (r,,), if lim r, = a then lim f(r,) = f(a). n Theorem 15 says that in order for f to be continuous, it is necessary and sufficient that any sequence (zn) converging to a must force the sequence (f(zn)) to converge to f(a). A picture of this situation is below though, as always, the formal proof will not rely on the diagram. CONTINUITY: WHAT IT ISN'T AND WHAT IT Is 111 This theorem is especially useful for showing that a function f is not con- tinuous at a point a; all we need to do is exhibit a sequence (r,) oconverging to a such that the sequence lim, f(rn) does not converge to f(a). Let's demonstrate this idea before we tackle the proof of Theorem 15, Example 12. Use Theorem 15 to prove that (z) = 10, if z=0 is not continuous at 0. Proof: First notice that f can be written as if r>0 S(z) = {-1 if x <0 if x = 0 To show that f is not continuous at 0, all we need to do is create a single sequence (r,) which converges to 0, but for which the sequence (f (xn)) does not converge to f(0) = 0. For a function like this one, just about any sequence will do, but let's use (1), just because it is an old familiar friend. ()- We have lim - = 0, but lim f = lim 1=1#0 = f(0). Thus by Theorem 15 f is not continuous at 0.
4:37
A inst-fs-iad-prod.inscloudgate.net
a yo trreeere o er y TT
that g(z) +0 for all r € (a – 6, a + 6).
Problem 114. Prove Lemma (Hint: Consider the case where g(a) > 0. Use
120 of 220 on with e = 20. The picture is below; make it formal.
g(a)
g(a) – 9(@
a-8
a+8
For the case g(a) <0, consider the function -g.)
A consequence of this lemma is that if we start with a sequence (r,) con-
verging to a, then for n sufficiently large, g(r.) #0.
Problem 115. Use Theorem 15 to prove that if f and g are continuous at a
and g(a) # 0, then f/g is continuous at a.
Theorem 17. Suppose f is continuous at a and g is continuous at f(a). Then
gof is continuous at a. [Note that (go f)(x) = g(f(x)).)
Problem 116. Prove Theorem 17
(a) Using the definition of continuity.
(b) Using Theorem 15,
The above theorems allow us to build continuous functions from other con-
tinuous functions. For example, knowing that f(r) = r and g(x) = c are
continuous, we can conclude that any polynomial,
p(x) = anr" + an-12"-1 + ... + a,x+ ao
CONTINUITY: WHAT IT ISN'T AND WHAT IT Is
115
is continuous as well. We also know that functions such as f(z) = sin (e*) are
continuous without having to rely on the definition.
Problem 117. Show that each of the following is a continuous function at every
point in its domain.
1. Any polynomial.
2. Any rational function. (A rational function is defined to be a ratio of
polynomials.)
3. cos z.
4. The other trig functions: tan(r), cot(r), sec(r), and cse(r).
Problem 118. What allows us to conclude that f(r) = sin (e) is continuous
at any point a without referring back to the definition of continuity?
Theorem [15 can also be used to study the convergence of sequences. For
example, since f(z) = e is continuous at any point and lim,nx "1 = 1,
then lim. e() = e. This also illustrates a certain way of thinking about
continuous functions. They are the ones where we can "commute" the function
and a limit of a sequence. Specilfically, if } is continuous at a and lim, In = a,
Transcribed Image Text:4:37 A inst-fs-iad-prod.inscloudgate.net a yo trreeere o er y TT that g(z) +0 for all r € (a – 6, a + 6). Problem 114. Prove Lemma (Hint: Consider the case where g(a) > 0. Use 120 of 220 on with e = 20. The picture is below; make it formal. g(a) g(a) – 9(@ a-8 a+8 For the case g(a) <0, consider the function -g.) A consequence of this lemma is that if we start with a sequence (r,) con- verging to a, then for n sufficiently large, g(r.) #0. Problem 115. Use Theorem 15 to prove that if f and g are continuous at a and g(a) # 0, then f/g is continuous at a. Theorem 17. Suppose f is continuous at a and g is continuous at f(a). Then gof is continuous at a. [Note that (go f)(x) = g(f(x)).) Problem 116. Prove Theorem 17 (a) Using the definition of continuity. (b) Using Theorem 15, The above theorems allow us to build continuous functions from other con- tinuous functions. For example, knowing that f(r) = r and g(x) = c are continuous, we can conclude that any polynomial, p(x) = anr" + an-12"-1 + ... + a,x+ ao CONTINUITY: WHAT IT ISN'T AND WHAT IT Is 115 is continuous as well. We also know that functions such as f(z) = sin (e*) are continuous without having to rely on the definition. Problem 117. Show that each of the following is a continuous function at every point in its domain. 1. Any polynomial. 2. Any rational function. (A rational function is defined to be a ratio of polynomials.) 3. cos z. 4. The other trig functions: tan(r), cot(r), sec(r), and cse(r). Problem 118. What allows us to conclude that f(r) = sin (e) is continuous at any point a without referring back to the definition of continuity? Theorem [15 can also be used to study the convergence of sequences. For example, since f(z) = e is continuous at any point and lim,nx "1 = 1, then lim. e() = e. This also illustrates a certain way of thinking about continuous functions. They are the ones where we can "commute" the function and a limit of a sequence. Specilfically, if } is continuous at a and lim, In = a,
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