Theorem 2.8. For positive integers a and b gcd(a, b) lcm(a, b) = ab Froof. To begin, put d = gcd(a, b) and write a = dr. b = ds for integersr and s. If m = ab/d, then m = as = multiple of a and b. Now let c be any positive integer that is a common multiple of a and D; say, for definiteness, c = au = bv. As we know, there exist integers x and y ratisfying d = ax + by. In consequence, rb, the effect of which is to make m a (positive) common cd c (ах + by) х + y = vx + uy %3D ab ab This equation states that m | c, allowing us to conclude that m < c. Thus, in accordance with Definition 2.4, m = lcm(a, b); that is, %3D ab Icm(a, b) = d ab %3D %3D - gcd(a, b) which is what we started out to prove. Theorem 2.8 has a corollary that is worth a separate statement. Corollary. For any choice of positive integers a and b, lcm(a, b) = ab if and only if gcd(a, b) = 1. %3D

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Prove Theorem 2.8 and Corollary
J TICOCI 2.8.
Theorem 2.8. For positive integers a and b
gcd(a, b) lcm(a, b) = ab
Proof. To begin, put d = gcd(a, b) and write a = dr. b = ds for integers r and 3. n
ala, then m = as = rb, the effect of which is to make m a (positive) common
multiple of a and b.
Now let c be any positive integer that is a common multiple of a and b; say,
for definiteness, c = au = bv. As we know, there exist integers x and y ratisiying
d = ax + by. In consequence,
%3D
m =
C
cd
c (ах + by)
x +
y = vx + uy
%3D
%3D
m
ab
ab
This equation states that m | c, allowing us to conclude that m < c. Thus, in accordance
with Definition 2.4, m = lcm(a, b); that is,
с.
ab
ab
Icm(a, b) =
d
%3D
gcd(a, b)
which is what we started out to prove.
Theorem 2.8 has a corollary that is worth a separate statement.
Corollary. For any choice of positive integers a and b, lcm(a, b) = ab if and only if
gcd(a, b) = 1.
%3D
Transcribed Image Text:J TICOCI 2.8. Theorem 2.8. For positive integers a and b gcd(a, b) lcm(a, b) = ab Proof. To begin, put d = gcd(a, b) and write a = dr. b = ds for integers r and 3. n ala, then m = as = rb, the effect of which is to make m a (positive) common multiple of a and b. Now let c be any positive integer that is a common multiple of a and b; say, for definiteness, c = au = bv. As we know, there exist integers x and y ratisiying d = ax + by. In consequence, %3D m = C cd c (ах + by) x + y = vx + uy %3D %3D m ab ab This equation states that m | c, allowing us to conclude that m < c. Thus, in accordance with Definition 2.4, m = lcm(a, b); that is, с. ab ab Icm(a, b) = d %3D gcd(a, b) which is what we started out to prove. Theorem 2.8 has a corollary that is worth a separate statement. Corollary. For any choice of positive integers a and b, lcm(a, b) = ab if and only if gcd(a, b) = 1. %3D
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