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Theorem 8. i) Every solution of Eq.(2) is bounded from above such that xo #0, x-1#0 and a > 0 min(,) such that xo # 0 , x-1 # ii)Every solution of Eq.(2) is bounded from down by M = 0 and a <0. Proof: i) Let {an}n=-k 00 be a solution of Eq.(2). It follows from Eq.(2) that Xn 1 Xn+1 = x + a Then 1 Xn S for all n 2 0. Xn-1 This means that every solution of eq(2) is bouneded from above by M = max(, ) such that xo + 0, x-1 # 0 and a > 0. ii) Easy to prove as in i).

Theorem 8. i) Every solution of Eq.(2) is bounded from above such that xo #0, x-1#0 and a > 0 min(,) such that xo # 0 , x-1 # ii)Every solution of Eq.(2) is bounded from down by M = 0 and a <0. Proof: i) Let {an}n=-k 00 be a solution of Eq.(2). It follows from Eq.(2) that Xn 1 Xn+1 = x + a Then 1 Xn S for all n 2 0. Xn-1 This means that every solution of eq(2) is bouneded from above by M = max(, ) such that xo + 0, x-1 # 0 and a > 0. ii) Easy to prove as in i).

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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Show me the steps of determine blue and inf is here

Xn Xn+1 (xn) + a where (xo) + -a In order to do this we introduce the following notations: Let xo = a Consider the following notations:
Transcribed Image Text:Xn Xn+1 (xn) + a where (xo) + -a In order to do this we introduce the following notations: Let xo = a Consider the following notations:
Theorem 8. i) Every solution of Eq.(2) is bounded from above such that xo + 0, x-1 #0 and a > 0 ii)Every solution of Eq. (2) is bounded from down by M = min(,,) such that xo + 0, x-1# 0 аnd a < 0. Proof: i) Let {xn} k be a solution of Eq.(2). It follows from Eq.(2) that n=-k Xn 1 Xn+1 xn + a Then 1 for all n > 0. Xn-1 This means that every solution of eq(2) is bouneded from above by M = max(, ) such that xo + 0, x-1 70 and a > 0 . ii) Easy to prove as in i) .
Transcribed Image Text:Theorem 8. i) Every solution of Eq.(2) is bounded from above such that xo + 0, x-1 #0 and a > 0 ii)Every solution of Eq. (2) is bounded from down by M = min(,,) such that xo + 0, x-1# 0 аnd a < 0. Proof: i) Let {xn} k be a solution of Eq.(2). It follows from Eq.(2) that n=-k Xn 1 Xn+1 xn + a Then 1 for all n > 0. Xn-1 This means that every solution of eq(2) is bouneded from above by M = max(, ) such that xo + 0, x-1 70 and a > 0 . ii) Easy to prove as in i) .
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